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Mathematics

1 answer:

Nana76 [90]4 years ago

4 0

Answer:

Answer is option d) a=1 b=4

Step-by-step explanation:

$given \: equation \: is \: \\ {x}^{2} - 2x - 3 = 0 \\ by \: factorization \: we \: get \\ (x - 3)(x + 1) = 0 \\ x - 3 = 0 \\ x = 3 \\ x + 1 = 0 \\ x = - 1 \\ x = 3 \: \: or \: x = - 1 \\ value \: of {(x - a)}^{2} when \: x = 3 \: and \: a = 1 \\ {(3 - 1)}^{2} = {2}^{2} = 4 \\ if \: we \: substitute \: x = - 1 \: we \: get \: same \: answer$

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