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3 years ago

PLEASE HELP!!!!!!!!!!!! WILL GIVE CORRECT ANSWER BRAINLIEST!!!!!!!!!

Mathematics

1 answer:

Kaylis [27]3 years ago

6 0

Answer:

multiply the width to the height to get your answer.

Step-by-step explanation:

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Roys checking account pays 1% interest monthly and has a $10 service fee. if roys balance last month was $2223, find the amount

____ [38]

Credit of $12.23 that is the answer

8 0

3 years ago

Read 2 more answers

Divide 5600 in the ratio 4 :5:7 <br>

Elis [28]

Answer:

Step-by-step explanation:

So in our case, let assume 'x' as a common factor.

Thus,

4x + 5x + 7x = 5600;

16x = 5600;

x = 5600/16 = 350.

So,

4x= 350*4 =1400;

5x= 350*5 = 1750; &

7x= 350*7 = 2450.

Your answer is, 5600 = 1400+1750+2450 which is in ratio of 4:5:7.

5 0

2 years ago

The nth term of 17,29,41,53,65

s2008m [1.1K]

Answer:

12n+5

Step-by-step explanation:

The difference is 12 so that means n is 12 and the +5 is what the number in the sequence is before 17

8 0

3 years ago

If 3x - 8 = -2, find the value of x - 6.

prisoha [69]

The answer comes out to be X= -2

6 0

3 years ago

In a jar there are red jelly beans and green jelly beans. In how many ways can you pick red jelly beans and the same number of g

IrinaK [193]

<em>Complete Question:</em>

In a jar there are 19 red jelly beans and 10 green jelly beans. In how many ways can you pick 4 red jelly beans and the same number of green jelly beans?

Answer:

$Both = 813960$

Step-by-step explanation:

Given

Red Jelly Beans = 19

Green = 10

Required

Select 4 out of 19 red jelly beans and 4 out of 10 green jelly beans

The keyword in the question is pick and this implies combination;

4 from 19 red jelly beans is calculated as follows

$^nC_r = \frac{n!}{(n-r)!r!}$

Where n = 19 and r = 4

$^{19}C_4 = \frac{19!}{(19-4)!4!}$

$^{19}C_4 = \frac{19!}{15!4!}$

$^{19}C_4 = \frac{19 * 18 * 17 * 16 * 15!}{15! * 4 * 3 * 2 * 1}$

$^{19}C_4 = \frac{19 * 18 * 17 * 16}{4 * 3 * 2 * 1}$

$^{19}C_4 = \frac{93024}{24}$

$^{19}C_4 = 3876$

Similarly;

4 from 10 green jelly beans is calculated as follows

$^{10}C_4 = \frac{10!}{(10-4)!4!}$

$^{10}C_4 = \frac{10!}{6!4!}$

$^{10}C_4 = \frac{10 * 9 * 8 * 7 * 6!}{6! * 4 * 3 * 2 * 1}$

$^{10}C_4 = \frac{10 * 9 * 8 * 7 }{4 * 3 * 2 * 1}$

$^{10}C_4 = \frac{5040}{24}$

$^{10}C_4 = 210$

Ways of selecting both is calculated as follows

$Both = 3876 * 210$

$Both = 813960$

5 0

4 years ago