Answer:
Explanation:
You need to find the probability that exactly three of the first 11 inspected packages are damaged and the fourth is damaged too.
<u>1. Start with the first 11 inspected packages:</u>
a) The number of combinations in which 11 packages can be taken from the 20 available packages is given by the combinatory formula:
b) The number of combinations in which 3 damaged packages can be chossen from 7 damaged packages is:
c) The number of cominations in which 8 good packages can be choosen from 13 good pacakes is:
d) The number of cominations in which 3 damaged packages and 8 good packages are chosen in the first 11 selections is:
e) The probability is the number of favorable outcomes divided by the number of possible outcomes, then that is:
Subsituting:
<u>2. The 12th package</u>
The probability 12th package is damaged too is 7 - 3 = 4, out of 20 - 11 = 9:
<u>3. Finally</u>
The probability that exactly 12 packages are inspected to find exactly 4 damaged packages is the product of the two calculated probabilities:
Answer:
-2±2i√5 / 3
Step-by-step explanation:
You can't factor this equation, so you use the quadratic formula to solve it, which is
-b±√b-4ac/2a
Answer:
1.2
Step-by-step explanation:
0.2 x 6 = 1.2
Answer:
10 milligrams
Step-by-step explanation: