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Naddik [55]
3 years ago
9

Data were collected on the amount spent by 64 customers for lunch at a major Houston restaurant. These data are contained in the

WEBfile named Houston. Based upon past studies the population standard deviation is known with = $6.Click on the webfile logo to reference the data.Round your answers to two decimal places.a. At 99% confidence, what is the margin of error?b. Develop a 99% confidence interval estimate of the mean amount spent for lunch.____ to ____Amount20.5014.6323.7729.9629.4932.709.2020.8928.8715.7818.1612.1611.2216.4317.669.5918.8919.8823.1120.1120.3420.0830.3621.7921.1819.2234.1327.4936.5518.3732.2712.6325.5327.7133.8121.7919.1626.3520.0126.8513.6317.2213.1720.1222.1122.4720.3635.4711.8517.886.8330.9914.6218.3826.8525.1027.5525.8714.3715.6126.4624.2416.6620.85

Mathematics
1 answer:
love history [14]3 years ago
6 0

Answer:

attached below

Step-by-step explanation:

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The function f(x)=125(0.9)x models the population of a species of fly in millions after x years.
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A word to the wise:  It's  <span> f(x)=125(0.9)^x,   where ^ represents exponentiation.

In this case the ave. value over the interval [11, 15] is

 125(0.9)^15 - 125(0.9)^11
------------------------------------- = (125/4) [ 0.9^15 - 0.9^11)
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Do the same thing for the time interval [1,5].  Then compare the two rates of change.</span>
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2 years ago
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Answer:

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3 years ago
a solid sphere is cut into 3 equal wedges. the volume of each wedge is V=4/9π^3. solve the formula for r
algol13

\\ \qquad\quad\sf{:}\dashrightarrow V=\dfrac{4}{9}πr^3

  • It is one third of the solid. sphere

\\ \qquad\quad\sf{:}\dashrightarrow V_{(Sphere)}

\\ \qquad\quad\sf{:}\dashrightarrow 3\left(\dfrac{4}{9}πr^3\right)

\\ \qquad\quad\sf{:}\dashrightarrow \dfrac{4}{3}\pi r^3

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\\ \qquad\quad\sf{:}\dashrightarrow r^3=\dfrac{3V}{4\pi}

\\ \qquad\quad\sf{:}\dashrightarrow r=\sqrt[3]{\dfrac{3V}{4\pi}}

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(-3x +11x-1)+(7x2 - 4x+4)
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Step-by-step explanation:

-3x + 11x - 1 + 7x2 - 4x + 4

Solving like terms

7x2 + 4x + 3

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