Answer:
American Roulette
1. The probability of losing a ’1st 12’ bet on a single spin is:
= 0.67
2. The probability of winning 7 out of the 10 total bets is:
= 0.23
Step-by-step explanation:
Possible outcomes in an American Roulette wheel = 38
Make-up of the outcomes = 18 black, 18 red and 2 green
Green outcomes are numbered 0 and 00
Number of wins for this person = 12
Probability of winning = 0.33 (12/36)
Number of possible losses for this person = 24
Probability of losing = 0.67 (24/36)
1. The probability of losing a '1st 12' bet on a single spin is:
= (36 - 12)/36
= 0.67
2. The probability of winning 7 out of the 10 total bets is:
Probability of winning = 12/36 * 7/10
= 0.23
