Question

What is the equation, in point-slope form, for a line that goes through (8,-4) and has a slope of -5/6?

Answer 1

The point-slope form:

$y-y_1=m(x-x_1)$

We have the point (8, -4) and the slope m = -5/6. Substitute:

$y-(-4)=-\dfrac{5}{6}(x-8)\\\\\boxed{y+4=-\dfrac{5}{6}(x-8)}$