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Hoochie [10]
3 years ago
10

I NEED HELP WITH THIS ASAP I WILL GIVE BRAINLIEST

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
6 0

Answer:

First, lets look at the side that is already labeled: 5 ft. There are two 5 ft. sides, so the total perimeter so far is 10. I actually compared the 5 ft. side to the side labeled x, and it appears that x = 10. The reason for this is that if you compare both sides, the x side is the same amount as two 5 ft. sides. To calculate the total perimeter, we need to add up the sides: 10 + 10 + 5 + 5 = 30 ft.

hope this helps.

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Question is Incomplete, Complete question is given below.

Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.

Answer:

∆ABC is right angled triangle with right angle at B.

Step-by-step explanation:

Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.  

We need to prove that triangle is the right angled triangle.

Let the triangle be denoted by Δ ABC with side as;

AB = (a - 1) cm

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Hence,

{AB}^2 = (a -1)^2 

Now We know that

(a- b)^2 = a^2+b^2 - 2ab

So;

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{AB}^2 = a^2 + 1 -2a

Now;

{BC}^2 = (2\sqrt{a})^2= 4a

Also;

{CA}^2 = (a + 1)^2

Now We know that

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{CA}^2 = a^2 + 1 +2a

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Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.

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