Answer: No this is not a linear function as the y values have different first differences.
Step-by-step explanation:
First we look at the x values. We start off and look at the second x value and subtract the first x value from it (That would be 1-0) and that equals to 1. Then we look at the third x value and subtract the second x value from it (2-1) and that equals to 1. Then we look at the fourth x value and subtract the third x value from it (That would be 3-2) and that is 1. Next we look at the fifth x value and subtract the fourth x value from it (That would be 4-3) and that is 1.
Now we look at the y values and do the same thing as with the x values. We start off and look at the second y value and subtract the first y value from it (That would be 1-0) and that equals to 1. Then we look at the third y value and subtract the second y value from it (4-1) and that equals to 3. Then we look at the fourth y value and subtract the third y value from it (That would be 9-4) and that is 5. Next we look at the fifth y value and subtract the fourth y value from it (That would be 16-9) and that is 7.
Even though the x values all have the same first differences, the y values do not and so this cannot be a linear function.
I hope this helps. Tell me if something doesn't make sense.
The 2 blue parallel lines because they are parallel :)
Answer:
Step-by-step explanation:
322+63
?=
0
385≠0
False
Answer: The correct answer is
Step-by-step explanation:
Answer:
Vertex form
y = -4(x + 3)^2 + 10
Standard form;
y = -4x^2-24x - 26
Step-by-step explanation:
Mathematically, we have the vertex form as
y = a(x-h)^2 + k
(h,k) represents the vertex
We have h as -3 and k as 10
y = a(x+3)^2 + 10
To get a, we substitute any of the points
Let us use (-1,-6)
-6 = a(-1+3)^2 + 10
-6-10 = 4a
4a = -16
a = -16/4
a = -4
So we have the equation as;
y = -4(x+3)^2 + 10
For the standard form;
We expand the vertex form;
y = -4(x + 3)(x + 3) + 10
y = -4(x^2 + 6x + 9) + 10
y = -4x^2 - 24x -36 + 10
y = -4x^2 -24x -26