4 6/11 is the value of 1 part of the ratio (1). 13 7/11 of the muxture is orang juice, in litres.
<u>Answer:</u>
The correct answer option is P (S∩LC) = 0.16.
<u>Step-by-step explanation:</u>
It is known that the probability if someone is a smoker is P(S)=0.29 and the probability that someone has lung cancer, given that they are also smoker is P(LC|S)=0.552.
So using the above information, we are to find the probability hat a random person is a smoker and has lung cancer P(S∩LC).
P (LC|S) = P (S∩LC) / P (S)
Substituting the given values to get:
0.552 = P(S∩LC) / 0.29
P (S∩LC) = 0.552 × 0.29 = 0.16
Answer:
I cant see it?
Step-by-step explanation:
I don't think this is middle school...
(2^8 x 3^-5 x 6^0)^-2 x ((3^-2)/(2^3))^4 x (2^28)
(256 x (1/243))^-2 x ((1/9)/(8))^4 x 268435456
1.05349794239^-2 x (<span>0.01388888888)^4 x 268435456
</span><span>
0.90101623534 x </span><span>3.72108862e-8 x 268435456
</span>8.99999997623
9
9 is your answer.
19.
2568.75 - 2500 = 68.75;
( ? / 100 ) * 2500 = 68.75 ;
? * 25 = 68.75;
? = 68.75 ÷ 25
? = 2.75;
r = 2.75 %
