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Georgia [21]
3 years ago
14

Question #2) 7085g=_kg _g

Mathematics
1 answer:
Doss [256]3 years ago
6 0
Kg means kilo grams. kilo means 1000 so 1 kilogram is 1000 grams so

7085grams

conversion from grams to kilograms=kg/1000g

so 7085g times kg/1000g=7085/1000 kg=7.085 kg


or if you want kg and g then find out how many times 1000 will go into 7085
it goes in 7 times so 7 kg

then there are 85 grams left over so

7kg and 85g
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Solve for y.<br> 3X+2y=12
Montano1993 [528]
3x + 2y = 12

2y = -3x + 12
  y = -1.5x + 6
3 0
3 years ago
Emma has addressed seven invitations to her
Firlakuza [10]

Answer:

12

Step-by-step explanation:

This can be solved by working backwards.

7 is one more than half the number of invitations.

Subtract 1.  6 is half the number of invitations.

Double.

12 is the full number of invitations.

Algebra (if you must!):

x = number of invitations

x/2 + 1 = 7

Subtract 1.

x/2 = 6

Multiply by 2.

x = 12

8 0
2 years ago
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Y = -x + 3<br> What is the slope for this?
ICE Princess25 [194]
The slope for this equation is x=3
5 0
3 years ago
A nurse collected data about the average birth weight of babies in the hospital that month. Her data is shown using the dot plot
mixer [17]

Answer:

The values of the box-plot are: B = {8.2, 8.3, 8.4, 8.5 and 8.9}.

Step-by-step explanation:

The data provided is as follows:

X     Frequency

8        0

8.1        0

8.2        2

8.3        2

8.4        2

8.5        3

8.6        0

8.7         1

8.8        0

8.9         1

 9           0

So, the actual data is:

S = {8.2 , 8.2 , 8.3 , 8.3 , 8.4 , 8.4 , 8.5 , 8.5 , 8.5 , 8.7 , 8.9 }

A boxplot, also known as a box and whisker plot is a method to demonstrate the distribution of a data-set based on the following 5 number summary,

  1. Minimum (shown at the bottom of the chart)
  2. First Quartile (shown by the bottom line of the box)
  3. Median (or the second quartile) (shown as a line in the center of the box)
  4. Third Quartile (shown by the top line of the box)
  5. Maximum (shown at the top of the chart).

The data set is arranged in ascending order.

The minimum value is, Min. = 8.2

The lower quartile is,

[\frac{n+1}{4}]^{th}\ obs.=[\frac{11+1}{4}]^{th}\ obs.=3^{rd }\ obs. =8.3,

Q₁ = 8.3.

The median value is,

[\frac{n+1}{2}]^{th}\ obs.=[\frac{11+1}{2}]^{th}\ obs.=6^{th}\ obs.=8.4

Median = 8.4

The upper quartile is,

[\frac{3(n+1)}{4}]^{th}\ obs.=[\frac{3(11+1)}{4}]^{th}\ obs.=9^{th }\ obs. =8.5,

Q₃ = 8.5.

The maximum value is, Max. = 8.9.

So, the values of the box-plot are: B = {8.2, 8.3, 8.4, 8.5 and 8.9}.

5 0
3 years ago
Question
ANTONII [103]

The approximate area of the park on the grid is: E. about 40 km² to 50 km².

<h3>How to Find the Approximate Area on a Coordinate Grid?</h3>

The number of square on a coordinate grid that is covered determines the area covered. We can make an estimate by counting how many of this square on the coordinate grid that is covered, then find out the area depending on how much square area each grid represents.

In the coordinate plane given, which shows a park, we are told that each of the square on the grid equals 1 k = square kilometer.

The number of each of these squares we can find that is covered by the park on the grid is: 48 squares.

Therefore, the area of 48 squares on the grid = 48 × 1 = 48 km². Since not all squares are fully covered by the park, we can state that the approximate area of the park on the grid is: E. about 40 km² to 50 km².

Learn more about the approximate area on a grid on:

brainly.com/question/368985

#SPJ1

7 0
1 year ago
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