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Yakvenalex [24]
3 years ago
9

Why is 0 not an identity for subtraction? explain

Mathematics
1 answer:
ki77a [65]3 years ago
5 0
When zero is added to or subtracted to a number, the number is not affected.
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2х - бу = 2<br>x + бу = 28​
scZoUnD [109]

Answer:

x = 10

y = 3

Step-by-step explanation:

Given

2x - 6y = 2

x + 6y = 28

Add both equations

2x + x -6y + 6y = 2 + 28

3x = 30

Divide both sides by 3

x = 30/3

x = 10

Substitute 10 for x in either equations to get y

Using equation 2 , we have

x + 6y = 28

10 + 6y = 28

Subtract 10 from both sides

10 - 10 + 6y = 28 - 10

6y = 18

Divide both sides by by 6

y = 18/6

y = 3

Therefore

x = 10

y = 3

7 0
3 years ago
which function has the greatest rate of change? A. y = 7/6x + 2/3 B. y = 7/5x + 7/5 C. y = 6/5x + 11/5 D. y = 5/4x + 15/4
ddd [48]

Answer:

Step-by-step explanation:

In y = mx + b form, the slope can be found in the m position

y = 7/6x + 2/3......slope(m) = 7/6 or 1.167

y = 7/5x + 7/5....slope(m) = 7/5 or 1.4

y = 6/5x + 11/5...slope(m) = 6/5 or 1.2

y = 5/4x + 15/4.....slope(m) = 5/4 or 1.25

so the greatest rate of change would be B. y = 7/5x + 7/5 with a slope of 7/5

3 0
3 years ago
You can paint 75 square feet of a surface every 45 minutes. Determine how long it takes you to paint a wall with the given dimen
marin [14]

Answer:

25.2 minutes

Step-by-step explanation:

step 1

Find the area of the given wall

A=(7)(6)=42\ ft^2

step 2

we know that

You can paint 75 square feet of a surface every 45 minutes

so

using proportion

Find out how long it takes you to paint a surface area of 42 square feet

\frac{75}{45}\ \frac{ft^2}{min}=\frac{42}{x}\ \frac{ft^2}{min}\\\\x=45(42)/75\\\\x=25.2\ min

5 0
3 years ago
Please help at least one of them number it please!!!!
andrew11 [14]

Answer:

Step-by-step explanation:

1. k - 5

2. 31g

3. b - 43

4. u - 36

5. 15r

6. 21/q

7. 7 + j or j + 7

8. 33/n

9. a + 23

10. 44m

11. c + 15

12. 10 -f

13. 39/e

14. k - 29

15. s - 38

16. v + 28

17. x - 11

18. y + 26

5 0
3 years ago
Read 2 more answers
Last month, Katie started training for the swim team. She swam 20 laps every day for 18 training days. This month, Katie wants t
nasty-shy [4]

She swim 20 laps every day for 18 training days

so total laps done last month = 20*18 = 360 laps

She will swim 3 more laps per training day and add more training days to her monthly schedule.

20 laps + 3 laps = 23 laps

(a)If Katie adds 5 training days to her schedule this month, will she swim 215 more laps?

18 days + 5 days more = 23 days

23 laps every day for 23 training days

so total laps = 23*23 = 529 laps. That is 169 more laps than 360 laps done last month. Hence she cannot swim 215 more laps

If Katie adds 10 more training days to her schedule this month, will she swim 215 more laps?

18 days + 10 days more = 28 days

23 laps every day for 28 training days

so total laps = 23*28 =644 laps. That is 284 more laps than 360 laps done last month. Hence she can swim 215 more laps

(c)If Katie adds 6 more training days to her schedule this month, will she swim 215 more laps?

18 days + 6 days more = 24 days

23 laps every day for 24 training days

so total laps = 23*24 =552 laps. That is 192 more laps than 360 laps done last month. Hence she cannot swim 215 more laps

Build an equation for finding the number of additional training days she needs to swim 215 more laps

Let x be the number of days more

So training days = 18 + x

215 more laps , so total laps = 360 + 215 = 575

3 more laps per training day so 20 + 3 = 23 laps per day

laps * training days = total laps

so equation becomes

23 * (18+x) = 575

Now solve for x

414 + 23x = 575

Subtract 414 from both sides

23x = 161

x= 7

so she needs 7 training days to swim 215 more laps

3 0
3 years ago
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