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jeyben [28]
3 years ago
11

What is the period of the function y= 3/2 cot(3/5x) +5?

Mathematics
1 answer:
finlep [7]3 years ago
7 0

Answer:

D; 5pi/3 units

Step-by-step explanation:

Here, we want to find the period of the function;

y = 3/2 cot (3/5x) + 5

By definition, the period of a function is the interval between two matching points in the function.

Let’s say it is the distance between two peaks, crests, etc on a function.

To find the value of the period. We shall standardize the function.

What this means is that we shall be writing the function in the standard form.

The standard form is as follows;

f(x) = A trig(Bx -C) + D

Where trig refers to the accompanying trigonometric function in question.

Comparing this standard form with our question, we can see that;

A is 3/2

B is 3/5

C is 0

D is 5

Now for cot and tan functions, we shall need to divide pi by the absolute value of B

Thus we have; pi divided by 3/5 which gives 5pi/3 units

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X^2=60 what is the value of x ?
olya-2409 [2.1K]

Answer:

x = ±2√15

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS
  • Equality Properties

<u>Algebra I</u>

  • Multiple roots/solutions

Step-by-step explanation:

<u>Step 1: Define</u>

x² = 60

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Square root both sides:                    x = ±√60
  2. Simplify:                                              x = ±2√15

<u>Step 3: Check</u>

<em>Plug in both solutions of x to verify it's a solution.</em>

x = 2√15

  1. Substitute:                    (2√15)² = 60
  2. Evaluate:                       4 · 15 = 60
  3. Multiply:                        60 = 60

x = -2√15

  1. Substitute:                    (-2√15)² = 60
  2. Evaluate:                       4 · 15 = 60
  3. Multiply:                        60 = 60

Here we see that both solutions do indeed work.

∴ x = ±2√15 are both solutions to the equation.

5 0
3 years ago
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