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Vlad [161]
4 years ago
15

2/5 divided 1/2 as a unit rate

Mathematics
2 answers:
Yanka [14]4 years ago
3 0

Answer:

2/5 divided 1/2 as a unit rate .what do you mean

a_sh-v [17]4 years ago
3 0
2/5 divided 1/2 is 3/7 as a unit rate
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A−(a+b)x=(b−a)x−(c+bx), if b≠ 0<br><br> HELP ASAP WILL MARK BRAINLIEST
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Answer:

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Step-by-step explanation:

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Which represents the solution to 7x &gt; 21 or 6x - 9 &lt; 21?
olganol [36]

Answer:

1) The correct option is the third line

2) The correct option is the third line please see attached graph

Step-by-step explanation:

For the system of inequalities,

7·x > 21 or 6·x -9 < 21 we have;

7·x > 21

x > 21/3 = 3

x > 3

Also we have for 6·x -9 < 21 we have;

6·x -9 < 21

6·x < 21 + 9

6·x < 30

x < 30/6 = 5

x < 5

The representation of the region x > 3 and the region x < 5 on the number line consists of indicating points 3 and 5 with  circles not filled to represent less than < and not less than or equal to ≤ and shading the potion of the number line in between the two points

Which gives the correct option as the third line which has an open circle at point 3 and 5

b) To graph the inequality v + 4 > 2 and 8·v - 20 ≤ 36

For the inequality v + 4 > 2, we have;

v > 2 - 4

v > - 2

For the inequality 8·v - 20 ≤ 36, we have;

8·v - 20 ≤ 36

8·v  ≤ 36 + 20              

8·v  ≤ 56

v ≤ 56/8

v ≤  7

The region representing v > -2 or v ≤ 7 on the number line consists of indicating points -2 with a circle (not filled) to represent less than < and point 7 with a filled circle to represent less than or equal to ≤ and shading the potion of the number line in between the two points

Which gives the correct option is the third line which has a closed circle at point -2 and an open circle at point 7

6 0
4 years ago
The width of a rectangle is 20 inches. What must the length be if the perimeter is at least 180 inches.a 85.5 inches b 70 inches
Veronika [31]
The anwser is b 75 inches
5 0
4 years ago
A business school has a goal that the average number of years of work experience of its MBA applicants is more than three years.
gizmo_the_mogwai [7]

Answer:

z=\frac{3.1-3}{\frac{2.449}{\sqrt{47}}}=0.280    

p_v =P(z>0.280)=0.390  

If we compare the p value and the significance level assumed \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its NOT significant higher than 0.3 at 1% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=3.1 represent the sample mean

\sigma=\sqrt{6} represent the sample standard deviation for the sample

n=47 sample size  

\mu_o =3 represent the value that we want to test

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 3, the system of hypothesis would be:  

Null hypothesis:\mu \leq 3  

Alternative hypothesis:\mu > 3  

If we analyze the size for the sample is > 30 and we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{3.1-3}{\frac{2.449}{\sqrt{47}}}=0.280    

P-value

Since is a one side test the p value would be:  

p_v =P(z>0.280)=0.390  

Conclusion  

If we compare the p value and the significance level assumed \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its NOT significant higher than 0.3 at 1% of signficance.  

3 0
3 years ago
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