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3 years ago

12 quarts equals how many pints

Mathematics

1 answer:

PIT_PIT [208]3 years ago

8 0

US liquid quart: 12
US liquid pint: 24

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Find g. (-9) g(+)= r^2 + 3r

oee [108]

Answer:

g(-9) = 64

Step-by-step explanation:

Given function:

g(r) = r² + 3r

Find g(-9):

g(-9) = (-9)² + 3(-9) = 81 - 27 = 64

7 0

2 years ago

Sun, a kayaker, paddles 8 miles upstream (against the current) in 2 hours. Returning to her original location, she paddles downs

Virty [35]

Answer: a=8 and b=1

Step-by-step explanation:

If x represents the paddling speed, and y represents the speed of the current.

Then Relative speed in upstream =x-y

Relative time in downstream=x-y

When she paddles upstream then distance covered by her= $speed\times\ time$

⇒8=(x-y)2 or 2(x-y)=8

Thus we get, a=1

When she paddles downstream then distance covered by her= $speed\times\ time$

⇒8=(x+y)1 or 1(x+y)=8

Thus we get b=1

4 0

3 years ago

Read 2 more answers

Help asappppopppppppp don’t play games IF u don’t know skip

irinina [24]

I’m not completely sure, but I would say about 3/5 because of the fact that the X is not directly in the middle, so it can’t be 1/2 but it’s very close to the middle which could make it possible that it is 3/5?

8 0

3 years ago

JJ is paid $1000 per month plus 8% commission on all he sells. He sold $15,000 last month. What was he paid in total?

IRISSAK [1]

Answer:

15000+1000=16000

Step-by-step explanation:

3 0

3 years ago

One household is to be selected at random from a town. The probability that the household has a cat is 0.20.2 . The proba

dimulka [17.4K]

Answer:

There is a 50% probability that the household has a dog, given that the household has a cat.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a household has a cat.

B is the probability that a household has a dog.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a household has a cat but not a dog and $A \cap B$ is the probability that a household has both a cat and a dog.

By the same logic, we have that:

$B = b + (A \cap B)$

The probability that the household has a cat or a dog is 0.5

$a + b + (A \cap B) = 0.5$

The probability that the household has a dog is 0.4

$B = 0.4$

$B = b + (A \cap B)$

$b = 0.4 - (A \cap B)$

The probability that the household has a cat is 0.2.

$A = 0.2$

$A = a + (A \cap B)$

$a = 0.2 - (A \cap B)$

$a + b + (A \cap B) = 0.5$

$0.2 - (A \cap B) + 0.4 - (A \cap B) + (A \cap B) = 0.5$

$A \cap B = 0.1$

What is the probability that the household has a dog, given that the household has a cat?

20% of the households have a cat, and 10% have both a cat and a dog. So

$P = \frac{A \cap B}{A} = {0.1}{0.2} = 0.5$

There is a 50% probability that the household has a dog, given that the household has a cat.

4 0

2 years ago