Hi plz halp me I don’t understand and plz do step by step

Radda [10]

Remark
The general equation for an ellipse is
$\frac{x^2}{a^2}+ \frac{y^2}{b^2}=1$

At the center, the the point is 0,27

Solving for the
$\frac{0}{a^2} + \frac{27^2}{b^2} = 1$
or b^2= 27^2 * 1
Taking the square root of both sides
b = 27

Now we need to use one more piece of information
The second point is (24,9) what that means is at the point x = 24, y = 9

Solving for that
$\frac{24^2}{a^2}+\frac{9^2}{27^2}=1$

576/a^2 + 81/729 = 1 Subtract 81/729 from both sides
576/a^2 = 1 - 81/729 = 576/a^2 = (729 - 81)/729 = 648 /729

576/a^2 = 648/729 Cross multiply

648 a^2 = 729 * 576 Divide by 648
a^2 = 648

Full equation for the ellipse and answer is

$\frac{x^2}{648}+ \frac{y^2}{729} = 1$

7 0

4 years ago

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write an equation to find the amount of simple interest, earned on a 600 dollar investment after 9 months, of the interest rate

tatuchka [14]

Equation:
A = P(1 + rt)
How to do it:
First, converting R percent to r a decimal
r = R/100 = 2.5%/100 = 0.025 per year,
putting time into years for simplicity,
9 months ÷ 12 months/year = 0.75 years,
then, solving our equation
A = 600(1 + (0.025 × 0.75)) = ___
What is it?

3 0

3 years ago

I need help and i also need the work shown...please and thank you

marin [14]

Answer:

55

Step-by-step explanation:

5 0

3 years ago

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When deriving the quadratic formula by completing the square, what expression can be added to both sides of the equation to crea

____ [38]

Answer:

According to steps 2 and 4. The second-order polynomial must be added by $-c$ and $b^{2}$ to create a perfect square trinomial.

Step-by-step explanation:

Let consider a second-order polynomial of the form $a\cdot x^{2} + b\cdot x + c = 0$ , $\forall \,x \in\mathbb{R}$ . The procedure is presented below:

1) $a\cdot x^{2} + b\cdot x + c = 0$ (Given)

2) $a\cdot x^{2} + b \cdot x = -c$ (Compatibility with addition/Existence of additive inverse/Modulative property)

3) $4\cdot a^{2}\cdot x^{2} + 4\cdot a \cdot b \cdot x = -4\cdot a \cdot c$ (Compatibility with multiplication)

4) $4\cdot a^{2}\cdot x^{2} + 4\cdot a \cdot b \cdot x + b^{2} = b^{2}-4\cdot a \cdot c$ (Compatibility with addition/Existence of additive inverse/Modulative property)

5) $(2\cdot a \cdot x + b)^{2} = b^{2}-4\cdot a \cdot c$ (Perfect square trinomial)

According to steps 2 and 4. The second-order polynomial must be added by $-c$ and $b^{2}$ to create a perfect square trinomial.

7 0

3 years ago

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Occasionally a savings account may actually pay interest compounded continuously. For each deposit, find the interest earned if

Ugo [173]

1. Occasionally a savings account may actually pay interest compounded continuously. For each deposit, find the interest earned if interest is compounded (a) semiannually, (b) quarterly, (c) monthly, (d) daily, and (e) continuously. Use 1 year = 365 days.

Principal $1031

Rate 1.4%

Time 3 years

Answer:

a) $ 44.07

b) $ 44.15

c) $ 44.20

d) $ 44.22

e) $ 44.22

Step-by-step explanation:

The formula to find the total amount earned using compound interest is given as:

A = P(1 + r/n)^nt

Where A = Total amount earned after time t

P = Principal = $1031

r = Interest rate = 1.4%

n = compounding frequency

t = Time in years = 3 years

For each deposit, find the interest earned if interest is compounded

(a) semiannually

This means the interest is compounded 2 times in a year

Hence:

A = P(1 + r/n)^nt

A = 1031(1 + 0.014/2) ^2 × 3

A = 1031 (1 + 0.007)^6

A = $ 1,075.07

A = P + I where

I = A - P

I = $1075.07 - $1031

P (principal) = $ 1,031.00

I (interest) = $ 44.07

(b) quarterly

This means the interest is compounded 4 times in a year

Hence:

A = P(1 + r/n)^nt

A = 1031(1 + 0.014/4) ^4 × 3

A = 1031 (1 + 0.014/4)^12

A = $ 1,075.15

I = A - P

I = $1075.15 - $1031

A = P + I where

P (principal) = $ 1,031.00

I (interest) = $ 44.15

(c) monthly,

This means the interest is compounded 12 times in a year

Hence:

A = P(1 + r/n)^nt

A = 1031(1 + 0.014/12) ^12 × 3

A = 1031 (1 + 0.014/12)^36

A = $ 1,075.20

A = P + I where

I = A - P

I = $1075.20 - $1031

P (principal) = $ 1,031.00

I (interest) = $ 44.20

(d) daily,Use 1 year = 365 days

This means the interest is compounded 365 times in a year

Hence:

A = P(1 + r/n)^nt

A = 1031(1 + 0.014/365) ^2 × 3

A = 1031 (1 + 0.00365)^365 × 3

A = $ 1,075.22

A = P + I where

I = A - P

I = $1075.22 - $1031

P (principal) = $ 1,031.00

I (interest) = $ 44.22

(e) continuously. .

This means the interest is compounded 2 times in a year

Hence:

A = Pe^rt

A = 1031 × e ^0.014 × 3

A = $ 1,075.22

A = P + I where

I = A - P

I = $1075.22 - $1031

P (principal) = $ 1,031.00

I (interest) = $ 44.22

5 0

3 years ago