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Bess [88]
3 years ago
11

Find the vertex of the parabola. y= -4x^2+24x-35 Answer ASAP

Mathematics
2 answers:
exis [7]3 years ago
7 0

Answer:

(3,1)

Step-by-step explanation:

y=-4x^2+24x-35

x-intercept of the vertex formula:

v=-b/2a

a=-4

b=24,

c=-35

v = - 24/2(-4)

v = -24/-8

v = 3

substitute x as v

y= -4(3)^2 + 24(3) - 35

y= -4(9) + 72 - 35

y = -36 +72 - 35

y = 36 - 35

y = 1

therefore the vertex is

(3,1)

rusak2 [61]3 years ago
4 0

Answer:

vertex = (3, 1 )

Step-by-step explanation:

Given a parabola in standard form : ax² + bx + c : a ≠ 0

The x- coordinate of the vertex is

x_{vertex} = - \frac{b}{2a}

y = - 4x² + 24x - 35 ← is in standard form

with a = - 4 and b = 24, thus

x_{vertex} = - \frac{24}{-8} = 3

Substitute x = 3 into the equation for corresponding value of y

y = - 4(3)² + 24(3) - 35 = - 36 + 72 - 35 = 1

Vertex = (3, 1 )

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