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Bess [88]
3 years ago
11

Find the vertex of the parabola. y= -4x^2+24x-35 Answer ASAP

Mathematics
2 answers:
exis [7]3 years ago
7 0

Answer:

(3,1)

Step-by-step explanation:

y=-4x^2+24x-35

x-intercept of the vertex formula:

v=-b/2a

a=-4

b=24,

c=-35

v = - 24/2(-4)

v = -24/-8

v = 3

substitute x as v

y= -4(3)^2 + 24(3) - 35

y= -4(9) + 72 - 35

y = -36 +72 - 35

y = 36 - 35

y = 1

therefore the vertex is

(3,1)

rusak2 [61]3 years ago
4 0

Answer:

vertex = (3, 1 )

Step-by-step explanation:

Given a parabola in standard form : ax² + bx + c : a ≠ 0

The x- coordinate of the vertex is

x_{vertex} = - \frac{b}{2a}

y = - 4x² + 24x - 35 ← is in standard form

with a = - 4 and b = 24, thus

x_{vertex} = - \frac{24}{-8} = 3

Substitute x = 3 into the equation for corresponding value of y

y = - 4(3)² + 24(3) - 35 = - 36 + 72 - 35 = 1

Vertex = (3, 1 )

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Answer:

Yes

Step-by-step explanation:

To check proportionality :

35 α 1000

35 = 1000k

k = constant of proportionality ;

Divide both sides by 1000 to obtain k

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0.035 = k

For the ratio Given :

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3 years ago
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Vesnalui [34]

Answer:

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Step-by-step explanation:

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2 years ago
What are the features of the parabola modeled by the equation f(x) = x2 - 114x ?
notsponge [240]

Answer:

Answers are in bold type

Step-by-step explanation:

f(x) = x^{2} -144x

The parabola opens up, so has a minimum at the vertex.

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h = -b/2a = - (-144)/2(1) = 57

k = 57^2 - 144(57) = 3249 - 6498 = -3249

Therefore, the vertex is (57, -3249)

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The domain is the set of real numbers.  

The  range = {y | y ≥ -3249}

The function decreases when -∞ < x < 57  and increases when 57 > x > ∞

The x - intercepts:  x^{2} -144x = 0

                                x(x - 114x) = 0

                                x = 0 or x = 114

x-intercepts are (0, 0) and (0, 114)

When x = 0, then we get the y-intercept.  So, 0^2 - 114(0) = 0

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3 years ago
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sergeinik [125]

Answer:

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Step-by-step explanation:

Start with:

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3 years ago
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