Answer:
![\huge\boxed{\text{(A)} \ -2}](https://tex.z-dn.net/?f=%5Chuge%5Cboxed%7B%5Ctext%7B%28A%29%7D%20%5C%20-2%7D)
Step-by-step explanation:
We have the equation
. Our goal is to isolate x on one side of the equation and find it's value by "reversing" the equation.
Apply the distributive property on the left side:
![-12x - 2x - 18 = 5(x+4)](https://tex.z-dn.net/?f=-12x%20-%202x%20-%2018%20%3D%205%28x%2B4%29)
Apply the distributive property on the right side:
![-12x-2x-18 = 5x+20](https://tex.z-dn.net/?f=-12x-2x-18%20%3D%205x%2B20)
Combine like terms on the left side:
![-14x-18=5x+20](https://tex.z-dn.net/?f=-14x-18%3D5x%2B20)
Subtract 5x from both sides:
![-19x-18=20](https://tex.z-dn.net/?f=-19x-18%3D20)
Add 18 to both sides:
![-19x=38](https://tex.z-dn.net/?f=-19x%3D38)
Divide both sides by -19:
![x=-2](https://tex.z-dn.net/?f=x%3D-2)
Hope this helped!
Answer:
(2,7)
Step-by-step explanation:
When you plot this on a grapg, you can see that the two equations intersect at that point. BTW Desmos is not illegal :)
Answer:
16
x
^4 − 96
x^
3 + 216
x
^2 − 216
x + 81
Step-by-step explanation:
Use the binomial expansion theorem to find each term. ∑
∑The binomial theorem states ( a + b ) n = n ∑ k = 0 n C k ⋅ ( a n − k b k ) . 4 ∑ k = 0 4 ! ( 4 − k ) ! k ! ⋅ ( 2 x ) 4 − k ⋅ ( − 3 ) k
Expand the summation. 4 ! ( 4 − 0 ) ! 0 ! ⋅ ( 2 x ) 4 − 0 ⋅ ( − 3 ) 0 + 4 ! ( 4 − 1 ) ! 1 ! ⋅ ( 2 x ) 4 − 1 ⋅ ( − 3 ) + 4 ! ( 4 − 2 ) ! 2 ! ⋅ ( 2 x ) 4 − 2 ⋅ ( − 3 ) 2 + 4 ! ( 4 − 3 ) ! 3 ! ⋅ ( 2 x ) 4 − 3 ⋅ ( − 3 ) 3 + 4 ! ( 4 − 4 ) ! 4 ! ⋅ ( 2 x ) 4 − 4 ⋅ ( − 3 ) 4
Simplify the exponents for each term of the expansion. 1 ⋅ ( 2 x ) 4 ⋅ ( − 3 ) 0 + 4 ⋅ ( 2 x ) 3 ⋅ ( − 3 ) + 6 ⋅ ( 2 x ) 2 ⋅ ( − 3 ) 2 + 4 ⋅ ( 2 x ) ⋅ ( − 3 ) 3 + 1 ⋅ ( 2 x ) 0 ⋅ ( − 3 ) 4
Simplify each term.
= 16
x
^4 − 96
x^
3 + 216
x
^2 − 216
x + 81