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3 years ago

Please help me with my homework :)

Mathematics

1 answer:

Kisachek [45]3 years ago

7 0

Scale factor is 1.5x
x is 10
y is 42
z is 36
i think angle is 150° i don’t know about this last one though

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How do u put 3 6/60 as a decimal?

pochemuha

3 over 1 + 6 over 60

[3 over 1 × 60 over 60] + 6 over 60

180 over 60 + 6 over 60 ➡ 186 over 60

186 over 60 ➡ 31 over 10

Then we divide 31 from 10 which give you the quotient of 3.1..

(((Meaning ➡ '"3.1" would be your answer)))

6 0

3 years ago

Please help asap Find the measure of angle y. Round your answer to the nearest hundredth. (please type the numerical answer only

mario62 [17]

Answer:

in degree 11.54

in radians 0.20

Step-by-step explanation:

soh= o/h

sin(y)=4/20

y=sin^-1(4/20)

8 0

3 years ago

Read 2 more answers

Tamira invests $5,000 in an account that pays 4% annual interest. How much will there be in the account after 3 years if the int

Talja [164]

Answer:

There will be $5624.32 in the account after 3 years if the interest is compounded annually.

There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.

There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.

There will be $5636.359 in the account after 3 years if the interest is compounded monthly

Step-by-step explanation:

Tamira invests $5,000 in an account

Rate of interest = 4%

Time = 3 years

Case 1:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 1

Formula : $A=P(1+r)^t$

$A=5000(1+0.04)^3$

A=5624.32

There will be $5624.32 in the account after 3 years if the interest is compounded annually.

Case 2:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 2

Formula : $A=P(1+\frac{r}{n})^{nt}$

$A=5000(1+\frac{0.04}{2})^{2 \times 3}$

A=5630.812

There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.

Case 3:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 4

Formula : $A=P(1+\frac{r}{n})^{nt}$

$A=5000(1+\frac{0.04}{4})^{4 \times 3}$

A=5634.125

There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.

Case 4:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 4

Formula : $A=P(1+\frac{r}{n})^{nt}$

$A=5000(1+\frac{0.04}{12})^{12 \times 3}$

A=5636.359

There will be $5636.359 in the account after 3 years if the interest is compounded monthly

8 0

3 years ago

I am so stressed can someone please help me <br><br> It’s 53 points

RoseWind [281]

Answer:

(3,1)

Step-by-step explanation:

8 0

3 years ago

Volume of a Sphere =

Fofino [41]

The answer is C I think

7 0

4 years ago