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LuckyWell [14K]
3 years ago
13

What is the meaning of 5 < x > 7 ?

Mathematics
1 answer:
Travka [436]3 years ago
6 0
The meaning of 57 is that 5 and 7 are both equal to x
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A 20-year loan of 1000 is repaid with payments at the end of each year. Each of the first ten payments equals 150% of the amount
Alja [10]

Answer:

x = 97

Step-by-step explanation:

Given

t = 20 --- time (years)

A =1000 --- amount

r = 10\% --- rate of interest

Required

The last 10 payments (x)

First, calculate the end of year 1 payment

y_1(end) = 10\% * 1000 * 150\%

y_1(end) = 150

Amount at end of year 1

A_1=A - y_1(end) - r * A

A_1=1000 - (150 - 10\% * 1000)

A_1 =1000 - (150- 100)

A_1 =950

Rewrite as:

A_1 = 0.95 * 1000^1

Next, calculate the end of year 1 payment

y_2(end) = 10\% * 950 * 150\%

y_2(end) = 142.5

Amount at end of year 2

A_2=A_1 - (y_2(end) - r * A_1)

A_2=950 - (142.5 - 10\%*950)

A_2 = 902.5

Rewrite as:

A_2 = 0.95 * 1000^2

We have been able to create a pattern:

A_1 = 1000 * 0.95^1 = 950

A_2 = 1000 * 0.95^2 = 902.5

So, the payment till the end of the 10th year is:

A_{10} = 1000*0.95^{10}

A_{10} = 598.74

To calculate X (the last 10 payments), we make use of the following geometric series:

Amount = \sum\limits^{9}_{n=0} x * (1 + r)^n

Amount = \sum\limits^{9}_{n=0} x * (1 + 10\%)^n

Amount = \sum\limits^{9}_{n=0} x * (1 + 0.10)^n

Amount = \sum\limits^{9}_{n=0} x * (1.10)^n

The amount to be paid is:

Amount = A_{10}*(1 + r)^{10} --- i.e. amount at the end of the 10th year * rate of 10 years

Amount = 1000 * 0.95^{10} * (1+r)^{10}

So, we have:

Amount = \sum\limits^{9}_{n=0} x * (1.10)^n

\sum\limits^{9}_{n=0} x * (1.10)^n = 1000 * 0.95^{10} * (1+r)^{10}

\sum\limits^{9}_{n=0} x * (1.10)^n = 1000 * 0.95^{10} * (1+10\%)^{10}

\sum\limits^{9}_{n=0} x * (1.10)^n = 1000 * 0.95^{10} * (1+0.10)^{10}

\sum\limits^{9}_{n=0} x * (1.10)^n = 1000 * 0.95^{10} * (1.10)^{10}

The geometric sum can be rewritten using the following formula:

S_n = \sum\limits^{9}_{n=0} x * (1.10)^n

S_n =\frac{a(r^n - 1)}{r -1}

In this case:

a = x

r = 1.10

n =10

So, we have:

\frac{x(r^{10} - 1)}{r -1} = \sum\limits^{9}_{n=0} x * (1.10)^n

\frac{x((1.10)^{10} - 1)}{1.10 -1} = \sum\limits^{9}_{n=0} x * (1.10)^n

\frac{x((1.10)^{10} - 1)}{0.10} = \sum\limits^{9}_{n=0} x * (1.10)^n

x * \frac{1.10^{10} - 1}{0.10} = \sum\limits^{9}_{n=0} x * (1.10)^n

So, the equation becomes:

x * \frac{1.10^{10} - 1}{0.10} = 1000 * 0.95^{10} * (1.10)^{10}

Solve for x

x = \frac{1000 * 0.95^{10} * 1.10^{10} * 0.10}{1.10^{10} - 1}

x = 97.44

Approximate

x = 97

4 0
3 years ago
Can anyone solve this please asap​
Reika [66]

Answer:

<h2>= 1.268</h2>

Step-by-step explanation:

= (3 + √3) (2 - √3)

= 6 - 3√3 + 2√3 - 3

= 3 - 3√3 + 2√3

= 3 - √3 (3 - 2)

= 3 - √3

= 3 - 1.732 ...... (√3 = 1.732)

= 1.268

6 0
3 years ago
A medium 1 topping pizza costs $12, and each additional topping costs $0.50. Don paid $16.50 for a medium pizza. If x gives the
Paladinen [302]

Answer:

A: 12+ 0.50x

Step-by-step explanation

4 0
3 years ago
I need help badly if you can help thank you very much
MArishka [77]

Answer:

(24,4,84)

Step-by-step explanation:

Since they restricted our domains to certain x values, we can find the range by plugging in the x values to find it y value or output.

f( - 2) = 5( { - 2}^{2} ) + 4

5(4) + 4 = 24

f(0) =  - 5( {0}^{2} ) + 4 = 4

5(4) {}^{2}  + 4 = 84

So our range is (24,4,84)

7 0
3 years ago
Read 2 more answers
The ability to find a job after graduation is very important to GSU students as it is to the students at most colleges and unive
Murrr4er [49]

Answer:

(0.806, 0.839)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Suppose we take a poll (random sample) of 3653 students classified as Juniors and find that 3005 of them believe that they will find a job immediately after graduation.

This means that n = 3653, \pi = \frac{3005}{3653} = 0.823

99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.823 - 2.575\sqrt{\frac{0.823*0.177}{3653}} = 0.806

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.823 + 2.575\sqrt{\frac{0.823*0.177}{3653}} = 0.839

The answer is (0.806, 0.839)

5 0
3 years ago
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