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s2008m [1.1K]
3 years ago
6

Which the two functions below has the smallest minimum.......

Mathematics
1 answer:
Sedbober [7]3 years ago
5 0
The answer is f(x) as x^4 has minimum value of 0 so x^4-2 has a minimum of -2


whereas in g(x) x^3 has a minimum of - infinity so g(x) also has minimum of - infinity. hope it helps
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1 /2 (4x - 2) - 2/3(6x + 9) ≤ 4
Montano1993 [528]

Answer:

x ≤ 1/2

Step-by-step explanation:

1/2(4x - 2) - 2/3(6x + 9) ≤ 4

2x-1   -  4x+6   ≤   4

2x-4x-1+6  ≤   4

-2x + 5  ≤  4

      -5      -5

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5 0
4 years ago
Can someone help me with 3 and 4?
KIM [24]

Answer:

3) f(-11)=2(-11)-7\\f(-11)=-22-7\\f(-11)=-29


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Step-by-step explanation:


8 0
3 years ago
For every 140 feet that jelly rides on her bicycle the wheels turn 20 times.about how many times do the wheels turn in 5 miles
Alinara [238K]

Answer:

188.57

Step-by-step explanation:

5 0
3 years ago
The graph of f(x)=sin(x) is transformed into a new function, g(x) , by compressing it vertically by a factor of 1/2 and shifting
Arturiano [62]
If we compress the graph of y = sin x vertically by 1/2, this gives us the equation y = \frac{1}{2} sin x. Shifting this downward (vertically) by 3 units will mean that the expression must have 3 subtracted from it, leaving the final equation of g(x) to be:
g(x) = \frac{1}{2} sin x - 3

6 0
3 years ago
I’m a bit confused. Plz help!
77julia77 [94]

Answer:

the answer is  A.

Step-by-step explanation:

6 0
3 years ago
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