All categories

3 years ago

Which the two functions below has the smallest minimum.......

Mathematics

1 answer:

Sedbober [7]3 years ago

5 0

The answer is f(x) as x^4 has minimum value of 0 so x^4-2 has a minimum of -2

whereas in g(x) x^3 has a minimum of - infinity so g(x) also has minimum of - infinity. hope it helps

You might be interested in

An environment engineer measures the amount ( by weight) of particulate pollution in air samples ( of a certain volume ) collect

Serggg [28]

Answer:

$k = 1$

$P(x > 3y) = \frac{2}{3}$

Step-by-step explanation:

Given

$f \left(x,y \right) = \left{ \begin{array} { l l } { k , } & { 0 \leq x} \leq 2,0 \leq y \leq 1,2 y \leq x } & { \text 0, { elsewhere. } } \end{array} \right.$

Solving (a):

Find k

To solve for k, we use the definition of joint probability function:

$\int\limits^a_b \int\limits^a_b {f(x,y)} \, = 1$

Where

${ 0 \leq x} \leq 2,0 \leq y \leq 1,2 y \leq x }$

Substitute values for the interval of x and y respectively

So, we have:

$\int\limits^2_{0} \int\limits^{x/2}_{0} {k\ dy\ dx} \, = 1$

Isolate k

$k \int\limits^2_{0} \int\limits^{x/2}_{0} {dy\ dx} \, = 1$

Integrate y, leave x:

$k \int\limits^2_{0} y {dx} \, [0,x/2]= 1$

Substitute 0 and x/2 for y

$k \int\limits^2_{0} (x/2 - 0) {dx} \,= 1$

$k \int\limits^2_{0} \frac{x}{2} {dx} \,= 1$

Integrate x

$k * \frac{x^2}{2*2} [0,2]= 1$

$k * \frac{x^2}{4} [0,2]= 1$

Substitute 0 and 2 for x

$k *[ \frac{2^2}{4} - \frac{0^2}{4} ]= 1$

$k *[ \frac{4}{4} - \frac{0}{4} ]= 1$

$k *[ 1-0 ]= 1$

$k *[ 1]= 1$

$k = 1$

Solving (b): $P(x > 3y)$

We have:

$f(x,y) = k$

Where $k = 1$

$f(x,y) = 1$

To find $P(x > 3y)$ , we use:

$\int\limits^a_b \int\limits^a_b {f(x,y)}$

So, we have:

$P(x > 3y) = \int\limits^2_0 \int\limits^{y/3}_0 {f(x,y)} dxdy$

$P(x > 3y) = \int\limits^2_0 \int\limits^{y/3}_0 {1} dxdy$

$P(x > 3y) = \int\limits^2_0 \int\limits^{y/3}_0 dxdy$

Integrate x leave y

$P(x > 3y) = \int\limits^2_0 x [0,y/3]dy$

Substitute 0 and y/3 for x

$P(x > 3y) = \int\limits^2_0 [y/3 - 0]dy$

$P(x > 3y) = \int\limits^2_0 y/3\ dy$

Integrate

$P(x > 3y) = \frac{y^2}{2*3} [0,2]$

$P(x > 3y) = \frac{y^2}{6} [0,2]\\$

Substitute 0 and 2 for y

$P(x > 3y) = \frac{2^2}{6} -\frac{0^2}{6}$

$P(x > 3y) = \frac{4}{6} -\frac{0}{6}$

$P(x > 3y) = \frac{4}{6}$

$P(x > 3y) = \frac{2}{3}$

8 0

2 years ago

K’L’M’N’ is a dilation image of KLMN. The center of the dilation is the origin.

grandymaker [24]

A enlargement
b 2
hope this helps! good luck!

6 0

3 years ago

Read 2 more answers

WILL MARK BRAINLIEST WHOEVER ANSWERS CORRECTLY

chubhunter [2.5K]

Answer:

Step-by-step explanation:

Let the relation between the total number of candies (y) and number of bags (x) is,

y = mx + b

Here, b = Extra pieces of candies sitting outside the box.

m = Candies per box

From the question,

x = 4,(Number of bags are 4)

y = 4m + 4

If total number of candies are 36,

36 = 4m + 4

4m = 32

m = 8

Each bag will contain 8 candies.

Therefore, equation representing the relation is,

y = 8x + 4

Now complete the table by substituting the values of x,

x y

1 12

2 20

3 28

4 36

5 44

6 52

7 60

8 68

9 76

10 84

7 0

3 years ago

Determine what type of model best fits the given situation: water leaking from a local reservior at the rate of 500 gallons per

schepotkina [342]

The type of model that best fits the given situation is; A linear equation Model

<h3>What is the model of the equation?</h3>

Right inside the local reservoir we will have an initial amount of water A.

Now, for every hour that passes by, the amount of water in the reservoir decreases by 500 gals.

Thus, after t hours, the amount of water in the reservoir is expressed as:

W = A - 500gal * t

This is clearly a linear equation model and so we can conclude that the model that fits best in the given situation is a linear model.

The domain of this model is restricted because we can't have a negative amount of water in the reservoir, and as such the maximum value of t accepted is: W = 0 = A - 500gal*t

t = A/500 hours

Therefore, the domain of this linear relation is: t ∈ {0h, A/500 }

Read more about Equation model at; brainly.com/question/25896797

#SPJ1

3 0

1 year ago

3.14 rounded to the nearest 1 decimal place

natita [175]

3.1 (it is the tenth place)

3 0

3 years ago

Read 2 more answers