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antiseptic1488 [7]

4 years ago

5

6x-5=5(x-3)+x HEllppp mEEEeE i dont undersatnd this at all

1 answer:

Allushta [10]4 years ago

6 0

First simplify with distribuation 6x-5=5x-15+x
add like terms 6x-5=6x-15
then well you sure this is the correct question
then add 5 to both sides 6x=6x-10
then are you sure this is correct
then sub 6x from both sides so 0 = -10
which it doesn't so this would be false
if you have to find x then well I think you got the wrong question.

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Answer:

Third choice

Step-by-step explanation:

The domain of f(x) is the set of all real values except 7, i.e $x\ne7$

and the domain of g(x) is the set of all real values except -3, i.e $x\ne -3$

The domain of $g\circ f$ is the set of all real numbers x in the domain of $f$ such that $f(x)$ is in the domain of $g(x)$ .

However any numbers that are excluded from the domain of f must also be excluded from the domain of $g\circ f$ .

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