Ask question

Ask question

All categories

3 years ago

11

Lee is in customer service. How can she best support her internal customer, Dan? O al Prioritize other tasks and customers O b)

Ask him a lot of personal questions O c) Give him her full attention when he's speaking O d) Check with him before completing basic tasks

1 answer:

finlep [7]3 years ago

7 0

Answer:

free.exe

VVVVVVVVVVVVVVV

You might be interested in

B/3 + 1/7=13 can someone tell me what b is , thanks :))

nikklg [1K]

B is 4 thats what i got

4 0

3 years ago

3. Solve each equation, and check your solution.

Alisiya [41]

1) 2m - 16 = 2m + 4

2m - 2m = 4 + 16

0 = 20 (no solution)

2) -4(r + 2) = 4(2 - 2r)

-(r + 2) = 2 - 2r

-r - 2 = 2 - 2r

-r + 2r = 2 + 2

r = 4

3) 12(5 + 2y) = 4y - (6 - 9y)

60 + 24y = 4y - 6 + 9y

60 + 24y = 13y - 6

24y - 13y = -6 - 60

11y = -66

y = -6

7 0

3 years ago

Martin has a business washing cars. Last year he washed 20 cars a week. This year, he wants to increase his business to 1,200 ca

IgorC [24]

Great Question!

The last year part is extra information. 1200÷12 (months in a year)= 100

He will have to wash 100 cars each month.

8 0

3 years ago

The numerical expresion 5+12 represents the sum of 5 and 12

Sphinxa [80]

The sum of a number is the answer to an equation of a number plus a number you are correct.

6 0

3 years ago

A survey of 35 people was conducted to compare their self-reported height to their actual height. The difference between reporte

monitta

Answer:

The test statistic is t = 3.36.

Step-by-step explanation:

You're testing the claim that the mean difference is greater than 0.7.

At the null hypothesis, we test if it is 0.7 or less, that is:

$H_0: \mu \leq 0.7$

At the alternate hypothesis, we test if it is greater than 0.7, that is:

$H_1: \mu > 0.7$

The test statistic is:

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

0.7 is tested at the null hypothesis:

This means that $\mu = 0.7$

Survey of 35 people. From the sample, the mean difference was 0.95, with a standard deviation of 0.44.

This means that $n = 35, X = 0.95, s = 0.44$

Calculate the test statistic

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{0.95 - 0.7}{\frac{0.44}{\sqrt{35}}}$

$t = 3.36$

The test statistic is t = 3.36.

7 0

3 years ago