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3 years ago

URGENT!!!!!

Mathematics

1 answer:

Anna11 [10]3 years ago

7 0

h=20w

in one week hector works 20 hours

in two hector works 40 etc

h = hours and w = weeks. the money is just extra information.

h=20w works because if it has been two weeks we substitute the w with the number 2 and can solve

h=20(2)

h=20x2

h=40

This proves that the equation is true

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a car is traveling on a road that makes a 12 degree angle with the ground. find the height of the car vertically once it reaches

fenix001 [56]

I'm reading your question

___________________________

Trigonometric relationship

_____________________________-

tan (12º) = side opposite/ side adjacent

Side opposite = tan (12º) * side adjancent

Side opposite = tan (12º)* 102

Side opposite = 21. 7 m

________________________

Answer

21. 7 m

7 0

1 year ago

Area of a rectangle is 540 sq m. If the length was reduced by 5m and the width was increased by 5m, the are of the rectangle wil

wlad13 [49]

$l-length\\w-width\\\\\text{The formula of an area of a rectangle:}\ V=lw\\\\\text{We have the area}\ 540\ m^2\to lw=540\\\\\text{New rectangle}\\\\l-5-length\\w+5-width\\\\\text{We have the area}\ 540\ m^2+35\ m^2=575\ m^2\to (l-5)(w+5)=575\\\\\text{Therefore we have the system of equation:}\\\\\left\{\begin{array}{ccc}lw=540&\to w=\dfrac{540}{l}&(*)\\(l-5)(w+5)=575&&(**)\end{array}\right\\\\\text{Substitute}\ (*)\ \text{to}\ (**)$

$(l-5)\left(\dfrac{540}{l}+5\right)=575\qquad\text{use distributive property}\\\\(l)\left(\dfrac{540}{l}\right)+(5)(l)-(5)\left(\dfrac{540}{l}\right)-(5)(5)=575\\\\540+5l-\dfrac{2700}{l}-25=575\\\\515+5l-\dfrac{2700}{l}=575\qquad\text{subtract 575 from both sides}\\\\-60+5l-\dfrac{2700}{l}=0\qquad\text{multiply both sides by }\ l\neq0\\\\-60l+5l^2-2700=0\\\\5l^2-60l-2700=0\qquad\text{divide both sides by 5}\\\\l^2-12l-540=0\\\\l^2+30l-18l-540=0\\\\l(l+30)-18(l+30)=0\\\\(l+30)(l-18)=0\iff l+30=0\ \vee\ l-18=0\\\\l=-30$

$\text{Substitute the value of}\ l\ \text{to}\ (*):\\\\w=\dfrac{540}{18}\\\\\boxed{w=30\ cm}$

$Answer:\ \boxed{length=18\ cm,\ width=30\ cm}$

3 0

3 years ago

How much material is needed to construct a triangular tent that is 6 feet wide 4 feet tall and 8 feet long with side measurement

jonny [76]

Answer: 152ft^2

The amount of material needed to construct the tent is 152ft^2

Step-by-step explanation:

The amount of material needed to construct a triangular tent= the surface area of the triangular tent.

S.A = area of the 2 side rectangles + area of the 2 side triangles + area of the base.

S.A = Ab + At + Ar ....1

Area of the base Ab= Length × width = 8×6 = 48ft^2

Area of the two triangles At = 2 × 0.5 × width × height

At = width × height = 6×4 = 24ft^2

Area of the two rectangles Ar = 2 × side measurement × length

Side measurement is given as 5ft.

or it can be calculated using;

Side length can be calculated using Pythagoras theorem.

Examining the figure attached, we can see that;

Side breadth b = √(h^2 + (w/2)^2)

b = √(4^2 + (6/2)^2) = √(16+9) = √25

b = 5ft

Ar = 2×5×8 = 80ft^2

From eqn1, S.A can be solved as;

S.A = 48 + 24 + 80

S.A = 152ft^2

7 0

4 years ago

Claire wants to mail a package that weighs 4 1/2 lb what could this weight be in kilograms

kipiarov [429]

well 4 1/2 pounds should be 4.5 so that in kilograms is 2.04117

7 0

3 years ago

When working out on the track, Sean normally averages x laps per minute, while Jill averages y laps

Shalnov [3]

It will be either 34737347474674)474748484873

4 0

4 years ago