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laila [671]
4 years ago
5

Steel Mill Inc. makes an offer to Tom to enter into a contract to work as a mechanical engineer for a certain salary for one yea

r subject to a five-year renewal based on his performance. Tom accepts the offer. This is a valid contract because it includes __________.
a. a duration and a termination.
b. a price and a subject.
c. specific quality standards.
d. an offer and an acceptance.
Business
1 answer:
KIM [24]4 years ago
4 0

Answer:

d. an offer and an acceptance.

Explanation:

A contract exists where each involved party agrees to fulfill its obligations as per the terms of the agreement. The two or more parties involved are in consensus regarding the subject matter.  A contract valid and in force, once the offeror makes the offer, and the offeree accepts it.  

Steel and mike are in are contract. Mike has accepted the offer by steel. Other elements that must be present for a contract to be valid are the existence of consideration, mutual obligations, and the ability to fulfill one's responsibility.

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3 years ago
What percentage of data would you predict would be between 40 and 70 and what percentage would you predict would be more than 70
Mariana [72]

Answer:

<em>The percentage of data of prediction between 40 and 70 is 0.4347 or about 43.57%., the percentage of prediction that would be more than 70 miles is 0.2389 or about 23.89%</em>

Explanation:

<em>Let us Recall that, </em>

<em>We can perform analysis using the z-score of certain values, only when the standard deviation and the men are. The z-score is the measure of how many standard deviations from the mean a certain value is known. by finding the percentage of values that is expected to be above or below a value is by applying the z-score </em>

<em>The first step is to find the z-score for each of these values. After that, we apply the Standard Normal Probabilities table to find the percentage between the values. The z-score given as follows, </em>

<em>z= x-ẋ/s </em>

<em> ẋ = the sample mean </em>

<em>s = the sample standard deviation </em>

<em>x = is the data value not given </em>

<em> The mean value is = 51.6571429 </em>

<em>The standard deviation value is = 25.8012116 </em>

<em> Then </em>

<em>The z score for 40 is given as </em>

<em> z = 40 – 51.6571429/ 25.8012116 = - 0.45 </em>

<em> The z score for 70 is given as, </em>

<em> Z = 70 – 51.6571429/ 25.8012116 = -0.71 </em>

<em> The table entry for both -0.45 and 0.71 is 0.3264, and 0.7611 </em>

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<em> find the percentage between 40 and 70, we subtract table entries to get 0.7611 - 0.3264 = 0.4347 or about 43.57%. </em>

<em>To find the percentage above 70, we subtract the table entry for 70 from 1 to get 1 - 0.7611 = 0.2389 or about 23.89% </em>

4 0
4 years ago
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yKpoI14uk [10]
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Keating Co. is considering disposing of equipment with a cost of $52,000 and accumulated depreciation of $36,400. Keating Co. ca
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Answer:

$12,750

Explanation:

The computation of net differential income is shown below:-

For computing the net differential income first we need to find out the net income if equipment is sold and net income if offer lease is accepted which is given below:-

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Net differential income from the lease alternative = Net income if offer lease is accepted - Net income if equipment is sold

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