The least squares regression equation for the data in the table is
1 answer:
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The degree is 3, the zeros are; 4, 2i, -2i and a point is (-48, 2)
For zeros; 2i, -2i <-- complex conjugates, always in pairs
= -4(i²=-1)
=5
=0
Therefore the equation is; a(
+5) <-- b value is zero
Rewrite the equation with all zeros;
a(x-4)(x²+5)=f(x) <-- put in coordinates of the points to find the value of x
a(2-4)(2²+5)=-48
a(2)(9)=-48
a=-48/18
a=-8/3
The final polynomial function is; (-8/3)(x-4)(x²+5)=f(x)
Hope I helped :)
For zeros; 2i, -2i <-- complex conjugates, always in pairs
= -4(i²=-1)
=5
=0
Therefore the equation is; a(
Rewrite the equation with all zeros;
a(x-4)(x²+5)=f(x) <-- put in coordinates of the points to find the value of x
a(2-4)(2²+5)=-48
a(2)(9)=-48
a=-48/18
a=-8/3
The final polynomial function is; (-8/3)(x-4)(x²+5)=f(x)
Hope I helped :)
<h2>Answer:</h2>
Option: C is the correct answer.
C.
The sequence is given by the explicit formula as:
where is the nth term of the sequence.
Also, the first term of the sequence is:
i.e.
Also,
Hence, the recursive formula which represents the same sequence is:
Option: C
Answer:
7
Step-by-step explanation:
In general, the point of an inverse function is to show you the value that gives a particular function value. That is, ...