Of course there is. On a simple level, consider a parent trying to locate their missing child. Someone might break into their social media accounts to see if there are messages that might help determine their whereabouts.
Consider a website hosting inappropriate pictures of children. Breaking into the server hosting the files and removing them is 100% ethical. 
I'm sure you can think of more examples. 
        
             
        
        
        
Answer:
128 GB 
Explanation:
Here, we are interested in calculating the total capacity of the disk.
From the question, we can identify the following;
Number of surfaces = 4
Tracks per surface = 131,072
Number of sectors = 2,048
Each Block size = 512 bytes 
Mathematically;
Total data capacity of the disk = no of tracks * no of sectors * block size
= 131,072 * 2048 * 512 bytes 
= 2^17 * 2^11 * 2^9 bytes = 2^37 bytes 
1 GB = 2^30 bytes 
So 2^37 = 2^7 * 2^30
= 128 GB
 
        
             
        
        
        
Answer:
#include <stdio.h>
#include <ctype.h>
void printHistogram(int counters[]) {
    int largest = 0;
    int row,i;
    for (i = 0; i < 26; i++) {
        if (counters[i] > largest) {
            largest = counters[i];
        }
    }
    for (row = largest; row > 0; row--) {
        for (i = 0; i < 26; i++) {
            if (counters[i] >= row) {
                putchar(254);
            }
            else {
                putchar(32);
            }
            putchar(32);
        }
        putchar('\n');
    }
    for (i = 0; i < 26; i++) {
        putchar('a' + i);
        putchar(32);
    }
}
int main() {
    int counters[26] = { 0 };
    int i;
    char c;
    FILE* f;
    fopen_s(&f, "story.txt", "r");
    while (!feof(f)) {
        c = tolower(fgetc(f));
        if (c >= 'a' && c <= 'z') {
            counters[c-'a']++;
        }
    }
    for (i = 0; i < 26; i++) {
        printf("%c was used %d times.\n", 'a'+i, counters[i]);
    }
    printf("\nHere is a histogram:\n");
    printHistogram(counters);
}
 
        
             
        
        
        
Answer: False
Explanation:
   General purpose register cannot be read and written by the Ml program because when ever the instruction decode the input and output unit are invoke for data to read in the memory and it can written to the output device from the memory. General purpose register stored both the addresses and the data in the file. In some cases ML only reads with the hep of special algorithm function.