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3 years ago

Vallues of 3×-2×²=7

Mathematics

1 answer:

mrs_skeptik [129]3 years ago

6 0

Answer:

Step-by-step explanation:

"Find the values of x that satisfy 3x - 2x^2 = 7." Please do not use " × " to represent a variable; " × " is an operator, the "multiply" operator.

Rearrange these three terms in descending order by powers of x:

-2x^2 + 3x - 7 = 0. Here the coefficients are a = -2, b = 3 and c = -7, and so the discriminant of this quadratic is b^2-4ac, or 9 - 4(-2)(-7), or 9 - 56, or -47.

Because the discriminant is negative, we'll have two different complex roots here. The quadratic formula becomes

-3 ± i√47 -3 ± i√47

x = ----------------- = -------------------

2(-2) -4

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Answer:

The explicit formula

$a_n = 3 +0.25 (n-1)$

The recursive formula

$a_1 = 3$ for $n=1$

$a_n = a_ {(n-1)} +0.25$ if $n>1$

Step-by-step explanation:

If a sequence is arithmetical then the difference between any of its consecutive terms will be constant

3, 3.25, 3.5, 3.75,

$3.25-3 = 0.25\\\\3.5-3.25 = 0.25\\\\3.75 -3.5 = 0.25$

The difference between the consecutive terms remains constant so the sequence is arithmetic.

The explicit formula for an arithmetic sequence is:

$a_n = a_1 + d (n-1)$

Where d is the constant difference between the terms.

$d = 0.25$

$a_1$ is the first term of the sequence.

$a_1 = 3$

$a_n = 3 +0.25 (n-1)$

Finally, the recursive formula is:

$a_1 = 3\\\\a_n = a_ {(n-1)} +0.25$

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Vallues of 3×-2×²=7​

Vallues of 3×-2×²=7