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3 years ago

Vallues of 3×-2×²=7

Mathematics

1 answer:

mrs_skeptik [129]3 years ago

6 0

Answer:

Step-by-step explanation:

"Find the values of x that satisfy 3x - 2x^2 = 7." Please do not use " × " to represent a variable; " × " is an operator, the "multiply" operator.

Rearrange these three terms in descending order by powers of x:

-2x^2 + 3x - 7 = 0. Here the coefficients are a = -2, b = 3 and c = -7, and so the discriminant of this quadratic is b^2-4ac, or 9 - 4(-2)(-7), or 9 - 56, or -47.

Because the discriminant is negative, we'll have two different complex roots here. The quadratic formula becomes

-3 ± i√47 -3 ± i√47

x = ----------------- = -------------------

2(-2) -4

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Question 2

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Repeat for the other triangle as well

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Both triangles have the angles 32, 70, 78 in whatever order you wish.

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Question 3

We have a pair of congruent 54 degree angles shown. There's another pair of angles at the very top that overlap (aka shared angles).

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Question 5

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Vallues of 3×-2×²=7​

Vallues of 3×-2×²=7