The given expression is ![\frac{\sqrt{2}}{\sqrt[3]{2}}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B%5Csqrt%5B3%5D%7B2%7D%7D%20%20%20%20)
This can be simplified using the radical properties as below
![\\\ \frac{\sqrt{2}}{\sqrt[3]{2}}=\frac{2^{\frac{1}{2}}}{2^\frac{1}{3}} \\\\ \frac{\sqrt{2}}{\sqrt[3]{2}}=\frac{2^{\frac{1}{2}}}{2^\frac{1}{3}} \\\\](https://tex.z-dn.net/?f=%20%5C%5C%5C%20%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B%5Csqrt%5B3%5D%7B2%7D%7D%3D%5Cfrac%7B2%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7B2%5E%5Cfrac%7B1%7D%7B3%7D%7D%20%5C%5C%5C%5C%20%20%20%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B%5Csqrt%5B3%5D%7B2%7D%7D%3D%5Cfrac%7B2%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7B2%5E%5Cfrac%7B1%7D%7B3%7D%7D%20%5C%5C%5C%5C%20)
Now using exponent properties we can write
![\\\ \frac{\sqrt{2}}{\sqrt[3]{2}}=\frac{2^{\frac{1}{2}}}{2^\frac{1}{3}}=2^{\frac{1}{2}-\frac{1}{3}} \\\\\frac{\sqrt{2}}{\sqrt[3]{2}}=2^{\frac{3-2}{6}}=2^\frac{1}{6}\\\\= \sqrt[6]{2}\\](https://tex.z-dn.net/?f=%20%5C%5C%5C%20%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B%5Csqrt%5B3%5D%7B2%7D%7D%3D%5Cfrac%7B2%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7B2%5E%5Cfrac%7B1%7D%7B3%7D%7D%3D2%5E%7B%5Cfrac%7B1%7D%7B2%7D-%5Cfrac%7B1%7D%7B3%7D%7D%20%5C%5C%5C%5C%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B%5Csqrt%5B3%5D%7B2%7D%7D%3D2%5E%7B%5Cfrac%7B3-2%7D%7B6%7D%7D%3D2%5E%5Cfrac%7B1%7D%7B6%7D%5C%5C%5C%5C%3D%20%5Csqrt%5B6%5D%7B2%7D%5C%5C%20)
Let b and p represent the distances traveled by baby and pickles, respectively.
.. b +p = 27
.. p = 5(3b -1)
Substituting, you have
.. b +5(3b -1) - 27
.. 16b -5 = 27
.. 16 b = 32
.. b = 2
The baby travel was 2 miles.
The pickles travel was 25 miles.
Answer:
(0,-4-4√6) and (0,-4+4√6)
Step-by-step explanation:
To determine the coordinates as Jon wants to place it 14 points away
√10^2+(a+4)^2 = 14
100+(a+4)^2 = 196
(a+4)^2 = 96
a+4 = ±√96
a+4 = ±4√6
a= -4±4√6
I know for a fact that 1, 2 and 4 are correct. I'm almost positive 3 and 5 are right too
1. B
2.D
3.D
4.B
5.D