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krok68 [10]
3 years ago
11

Can someone help me plz need this done by tmrw

Mathematics
1 answer:
iren2701 [21]3 years ago
5 0

Answer:

X= -2

Step-by-step explanation:

herp derp herp derp

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An education firm measures the high school dropout rate as the percentage of 16 to 24 year olds who are not enrolled in school a
posledela

Answer:

The value of the test statistic z = -0.6606

Step-by-step explanation:

From the question we are told that

      The high dropout rate is \mu  = 6.1%  = 0.061

      The  sample size is  n = 1000

       The  number of dropouts x = 56

       The probability of having a dropout in 1000 people  \= x  = \frac{56}{1000}  =  0.056

Now setting up Test Hypothesis

 Null  H_o :  p = 0.061

 Alternative  H_a : p < 0.061        

The Test statistics is mathematically represented as

                 z = \frac{\= x - p}{\sqrt{\frac{p(1 -p)}{n} } }

substituting values

               z = \frac{0.056 - 0.061}{\sqrt{\frac{0.061(1 -0.061)}{1000} } }

               z = -0.6606

6 0
2 years ago
How I divided a hexagon into 3 equal parts?
vova2212 [387]
Put a dot in the middle and put a line up on one side and across the sides
7 0
3 years ago
Read 2 more answers
1. Which of the following does NOT represent a whole number? 9 6.0 12/4 -12/3​
Ivahew [28]

the answer is -12/3 cause it's negative

5 0
3 years ago
Consider the half of the sphere of radius 2 centered at the origin which lies above the xy-plane (a hemisphere). Suppose the den
Harlamova29_29 [7]

Answer:

25.133 units

Step-by-step explanation:

Since the density ρ = r, our mass is

m =  ∫∫∫r³sinθdΦdrdθ. We integrate from θ = 0 to π (since it is a hemisphere), Φ = 0 to 2π and r = 0 to 2  and  the maximum values of r = 2 in those directions. So

m =∫∫[∫r³sinθdΦ]drdθ      

m = ∫[∫2πr³sinθdθ]dr     ∫dФ = 2π

m = ∫2πr³∫sinθdθ]dr

m = 2π∫r³dr    ∫sinθdθ = 1

m = 2π × 4     ∫r³dr = 4

m = 8π units

m = 25.133 units

5 0
3 years ago
Prove usin's Mathematical induction 2^n ≤(n+1)!, for n≥0​
Westkost [7]

Answer:

Step-by-step explanation:

2^0 is less than or equal to 1!, because 1<= 1

if 2^n <= (n+1)!, we wish to show that 2^(n+1) <= (n+2)!, since

(n+2)! = (n+1)! * (n+2), and (n+1)!>= 2^n, then we want to prove that n+2<=2, which is always true for n>=0

8 0
1 year ago
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