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HACTEHA [7]
3 years ago
15

4 7/8 + 1/3= Simplest form

Mathematics
2 answers:
Harrizon [31]3 years ago
6 0

4 7/8 + 1/3 =

= 4 + 7/8 + 1/3

= 4 + 21/24 + 8/24

= 4 + 29/24

= 4 + 1 + 5/24

= 5 5/24

Elza [17]3 years ago
5 0
The answer is 5 5/24. Hope I was able to help

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Find the condition that one root of the quadratic equation may be 1 more than the other.
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Which will give can^2 + (2ac-b^2)n + ac = 0, which is the required condition.</span>
4 0
3 years ago
Fill in the table using this function rule.<br> y=14-2x
Mamont248 [21]

Answer:

when x is:

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Step-by-step explanation:

Substitute each value of x to obtain respective y values

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3 years ago
What is 70% as a fraction in simplest form
andriy [413]
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3 0
3 years ago
Read 2 more answers
Please help me with this question!
gavmur [86]
First off, let's convert the percentages to decimal format, so our 77% turns to 77/100 or 0.77, and our 55% turns to 55/100 or 0.55 and so on

now, the sum of both salines, must add up to the 77% mixture, let's say is "y"
so, 11 + 4 = y, and whatever the concentration level is, must also sum up to the mixture's concentration of 77%

anyway   thus

\bf \begin{array}{lccclll}&#10;&amount&concentration&&#10;\begin{array}{llll}&#10;concentrated\\&#10;amount&#10;\end{array}\\&#10;&-----&-------&-------\\&#10;\textit{first sol'n}&11&x&11x\\&#10;\textit{second sol'n}&4&0.55&2.20\\&#10;------&-----&-------&-------\\&#10;mixture&y&0.77&0.77y&#10;\end{array}\\\\&#10;-------------------------------\\\\&#10;\begin{cases}&#10;11+4=y\implies 15=\boxed{y}\\&#10;11x+2.2=0.77y\\&#10;----------\\&#10;11x+2.2=0.77\cdot \boxed{15}&#10;\end{cases}

solve for "x"
6 0
3 years ago
How do I solve this?
Crazy boy [7]

Answer:

71°

142°

Step-by-step explanation:

\because QS \: is \: the \: bisector \: of \:  \angle \: PQR\\\therefore m\angle RQS =m\angle PQS\\\because m\angle RQS = 71\degree...(given) \\ \huge \red{ \boxed{\therefore m\angle PQS = 71\degree}} \\   \because \: m\angle \: PQR = m\angle PQS  + m\angle RQS \\ \because \: m\angle \: PQR = 71\degree +  71\degree \\  \huge \purple{ \boxed{\therefore \: m\angle \: PQR = 142\degree}}

7 0
3 years ago
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