<span>Let p, np be the roots of the given QE.So p+np = -b/a, and np^2 = c/aOr (n+1)p = -b/a or p = -b/a(n+1)So n[-b/a(n+1)]2 = c/aor nb2/a(n+1)2 = cor nb2 = ac(n+1)2
Which will give can^2 + (2ac-b^2)n + ac = 0, which is the required condition.</span>
Answer:
when x is:
1; y = 12
2; y = 10
5; y = 4
6; y = 2
Step-by-step explanation:
Substitute each value of x to obtain respective y values
70% is the same as 70/100 then we simplify by taking off one zero of each number 7/10 and we can't divide it any more so the answer is 7/10
First off, let's convert the percentages to decimal format, so our 77% turns to 77/100 or 0.77, and our 55% turns to 55/100 or 0.55 and so on
now, the sum of both salines, must add up to the 77% mixture, let's say is "y"
so, 11 + 4 = y, and whatever the concentration level is, must also sum up to the mixture's concentration of 77%
anyway thus

solve for "x"
Answer:
71°
142°
Step-by-step explanation:
