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Natasha_Volkova [10]
3 years ago
8

Express your answers as reduced, improper fractions, if necessary.

Mathematics
1 answer:
loris [4]3 years ago
4 0
Answer: x= 13/2,-13/2
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Neil's Ice Creamery sold 50 sundaes last week. There were nuts on 22 of the sundaes. What is the ratio of the number of sundaes
Mkey [24]

The ratio of the number of sundaes with nuts to the number of sundaes without nuts is 11/14

What is ratio?

Ratio is a quantitative relationship between two values  indicating the number of times one value contains within the other value

In other words, we are expressing the number of sundaes with nuts as a fraction of the ones without nuts

There are 22 sundaes with nuts

number of sundaes without nuts=50-22

number of sundaes without nuts=28

sundaes with nuts/sundaes without nuts=22/28

2 is common to both numbers

sundaes with nuts/sundaes without nuts=11/14

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3 0
2 years ago
☆pls help no one has helped me and I'm so confused! ​
motikmotik

Answer:

Step-by-step explanation:

a). \frac{5\pm\sqrt{-4}}{3} = \frac{5}{3}\pm \frac{\sqrt{-4}}{3}

               = \frac{5}{3}\pm\frac{2\sqrt{(-1)} }{3}

               = \frac{5}{3}\pm\frac{2i}{3} [Since, i = \sqrt{(-1)}]

b). \frac{10\pm\sqrt{-16}}{2} = \frac{10}{2}\pm \frac{\sqrt{-16}}{2}

                  = 5\pm \frac{4\sqrt{-1}}{2}

                  = 5 ± 2i [Since, i = \sqrt{(-1)}]

c). \frac{-3\pm \sqrt{-144}}{6} = -\frac{3}{6}\pm \frac{\sqrt{-144}}{6}

                    = -\frac{3}{6}\pm \frac{12\sqrt{-1}}{6}

                    = -\frac{1}{2}\pm 2\sqrt{-1}

                    = -\frac{1}{2}\pm 2i [Since, i = \sqrt{(-1)}]

4 0
3 years ago
1. Which point on the axis satisfies the inequality y
grigory [225]

Answer:

1) Point (1,0) -----> see the attached figure N 1

2) The value of x is 4

3) I quadrant

4) (1,1)

5)  y>-5x+3

Step-by-step explanation:

Part 1)

we know that

If the point satisfy the inequality

then

the point must be included in the shaded area

The point (1,0) is included in the shaded area

Part 2)

we have

x-2y\geq 4

see the attached figure N 2

we know that

The value for x on the boundary line and the x axis is equal to the x-intercept of the line x-2y= 4

For y=0

Find the value of x

x-2(0)= 4  

x=4

The solution is x=4

Part 3)

we have

x\geq 0 -----> inequality A

The solution of the inequality A is in the first and fourth quadrant

y\geq 0 -----> inequality B

The solution of the inequality B is in the first and second quadrant

so

the solution of the inequality A and the inequality B is the first quadrant

Part 4) Which ordered pair is a solution of the inequality?

we have

y\geq 4x-5

we know that

If a ordered pair is a solution  of the inequality

then

the ordered pair must be satisfy the inequality

we're going to verify all the cases

<u>case A)</u> point (3,4)

Substitute the value of x and y in the inequality

x=3,y=4

4\geq 4(3)-5

4\geq 7 ------> is not true

therefore

the point (3,4) is not a solution of the inequality

<u>case B)</u> point (2,1)

Substitute the value of x and y in the inequality

x=2,y=1

1\geq 4(2)-5

1\geq 3 ------> is not true

therefore

the point  (2,1) is not a solution of the inequality

<u>case C)</u> point (3,0)

Substitute the value of x and y in the inequality

x=3,y=0

0\geq 4(3)-5

0\geq 7 ------> is not true

therefore

the point  (3,0) is not a solution of the inequality

<u>case D)</u> point (1,1)

Substitute the value of x and y in the inequality

x=1,y=1

1\geq 4(1)-5

1\geq -1 ------> is true

therefore

the point  (1,1) is  a solution of the inequality

Part 5) Write an inequality to match the graph

we know that

The equation of the line has a negative slope

The y-intercept is the point (3,0)

The x-intercept is a positive number

The solution is the shaded area above the dashed line

so

the equation of the line is y=-5x+3

The inequality is  y>-5x+3

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4 years ago
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Vesnalui [34]
The answer is Y=4x+5
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2 years ago
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