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Karo-lina-s [1.5K]
3 years ago
11

raul plans to spend no more than $78.00 on two shirts and a pair of jeans he bought the two shirts for $19.89 each how much can

he spend on the jeans write an inequality
Mathematics
1 answer:
densk [106]3 years ago
8 0

Raul can spend not more than $ 38.22 on the pair of jeans

<em><u>Solution:</u></em>

Raul plans to spend no more than $78.00 on two shirts and a pair of jeans

He bought the two shirts for $19.89 each

Therefore,

cost of 2 shirts = 19.89 x 2 = $ 39.78

Let "x" be the cost of pair of jeans

Then we frame a inequality as:

cost of 2 shirts + cost of pair of jeans \leq 78

39.78 + x\leq 78

Here we have used "less than or equal to" symbol, because he spend no more than $ 78

Solve the inequality for "x"

39.78 + x\leq 78\\\\Subtract\ 39.78\ from\ both\ sides\\\\x\leq 78-39.78\\\\x\leq 38.22

Thus, he can spend not more than $ 38.22 on the pair of jeans

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Charra [1.4K]

Answer:

cost of a bag of hot Cheetos = 0.75 and cost of a pack of sour patch kids = 1.5

Step-by-step explanation:

Let the cost of a bag of hot cheetos be c

Let the cost of a pack of sour patch kids be k

Thus, for Jasmine, the equation will be;

3c + 2k = 5.25 - - - - (eq1)

For Michael, the equation will be;

7c + 3k = 9.75 - - - - - (eq2)

We will use method of elimination to solve this.

Multiply (eq 1) by 3 and (eq 2) by 2 to give;

9c + 6k = 15.75 - - (eq4)

14c + 6k = 19.5 - - -(eq5)

Subtract (eq4) from (eq 5) to get;

5c = 19.5 - 15.75

5c = 3.75

c = 3.75/5

c = 0.75

Put 0.75 for c in (eq 4) to get;

9(0.75) + 6k = 15.75

6.75 + 6k = 15.75

6k = 15.75 - 6.75

6k = 9

k = 9/6

k = 1.5

Thus; cost of a bag of hot Cheetos = 0.75 and cost of a pack of sour patch kids = 1.5

7 0
3 years ago
Solve each system of equations algebraically. For each one, explain what the solution (or lack thereof) tells you
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Answer:

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b: (2, 3)

Step-by-step explanation:

a:

In both equations, the slope of x is the same, but the y-intercept is not, which means they are parallel. Therefore, this system of equations has no solutions.

b:

Since both of the equations are equal to y, we can set them equal to each other:

\frac{1}{2}x^2+1= 2x-1\\x^2 + 2 = 4x - 2\\x^2-4x+4=0

We can solve by factoring (by finding a number that multiplies to 4 and adds up to -4):

(x-2)^2 = 0

x = 2

Now, to find y, plug-in x to any of the equations:

y = 2*2-1 = 3

Therefore, the solution to this system of equation is (2, 3)

I hope this helped.

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2 years ago
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Answer:

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Step-by-step explanation:

As, - (2a3 - 3a2 + 4a + 6) + (2a3 + 5a2 + 7)

= 2a2 + 4a + 13

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WILL GIVE BRAINLIEST AND FOLLOW!! Last Question... A,B,C, or D
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