Polygon angle sum theorem, solve for many points.
1 answer:
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Check the picture below.
now, let's recall that running a segment from a midpoint across to a midpoint in a triangle, creates a midsegment, and a midsegment which is parallel to the "base" of the triangle, is always half of that base.
now, noticing the picture on the top-left triangle, we know those points are midpoints, so those in red are midsegments and therefore half the base, to make it short
IC = HE/2 = 7
JB = IC/2 = 3.5
now onto the top-right triangle, which is the same thing just basing itself on its other end
CG = AH/2 = 10
DF = CG/2 = 5
now, let's go to the picture on the bottom-center
we know that DG = 4, and since D and G are midpoints, DG is the midsegment of CEH thus
CH = 2DG = 8
likewise, on the green triangle ACH, the midsegment IB is half of the base CH, we know CH = 8, so IB = 4.
