Answer:
k = - 
, k = 2
Step-by-step explanation:
Using the discriminant Δ = b² - 4ac
The condition for equal roots is b² - 4ac = 0
Given
kx² + 2x + k = - kx ( add kx to both sides )
kx² + 2x + kx + k = 0 , that is
kx² + (2 + k)x + k = 0 ← in standard form
with a = k, b = 2 + k and c = k , thus
(2 + k)² - 4k² = 0 ← expand and simplify left side
4 + 4k + k² - 4k² = 0
- 3k² + 4k + 4 = 0 ( multiply through by - 1 )
3k² - 4k - 4 = 0 ← in standard form
(3k + 2)(k - 2) = 0 ← in factored form
Equate each factor to zero and solve for k
3k + 2 = 0 ⇒ 3k = - 2 ⇒ k = -
k - 2 = 0 ⇒ k = 2
Answer:
0
Step-by-step explanation:
Let's define 3 areas:
- S = area of semicircle with radius 6 in (diameter AB)
- T = area of quarter circle with radius 6√2 in (radius AC)
- U = area of triangle ABC (side lengths 6√2)
The white space between the "moon" and the triangle has area ...
white = T - U
Then the area of the "moon" shape is ...
moon = S -white = S -(T -U) = S -T +U
The area we're asked to find is ...
moon - triangle = (S -T +U) -U = S -T
__
The formula for the area of a circle of radius r is ...
A = πr²
So, ...
S = (1/2)π(6 in)² = 18π in²
and
T = (1/4)π(6√2 in)² = 18π in²
The difference in areas is S -T = (18π in²) -(18π in²) = 0.
There is no difference between the areas of the "moon" and the triangle.
I just did it on paper but hope that helps:)
Answer:
D
Step-by-step explanation:
When all the members in a domain has only but one member in the do main then function has been satisfied.
considering a situation of,
4 1
6 1
8 2
the domain has only one member in the Co domain hence which makes it a function
F(x+h) = 2(x+h) +3= 2x + 2h +3
f(x) = 2x + 5
f(x+h) - f(x) = 2x + 2h + 3- 2x - 3= 2h
[f(x+h) - f(x)]/h = 2h/h = 2
