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REY [17]
2 years ago
14

Ausbin decides to use khan academy

Mathematics
2 answers:
77julia77 [94]2 years ago
5 0
So? what’s the problem?
gulaghasi [49]2 years ago
4 0

Answer:

So?

Step-by-step explanation:

You might be interested in
What value of c makes x2 − 24x + c a perfect square trinomial?<br><br> −144<br> −48<br> 48<br> 144
NARA [144]
I believe that the answer is 144 

8 0
3 years ago
Read 2 more answers
Find the dimensions of the rectangle with area 289 square inches that has minimum perimeter, and then find the minimum perimeter
nalin [4]
 <span>To minimize the perimeter you should always have a square. 
sqrt(289) = 17 
The dimensions should be 17 X 17 

To see , try starting at length 1, and gradually increase the length. 
The height decreases at a faster rate than the length increases, up until you reach a square. 

Or if you want to use algebra, Say the width is 17-x 
Then the length is 289/(17-x) 

Now, this is bigger than 17+x, as shown here: 
289/(17-x) > 17+x 
289 > 289 - x^2 
which is true. 
so the perimeter would be bigger than 2 * (17- x + 17 + x) = 2 * (2 * 17) = 4 * 17 

Again, the dimensions should be a square. 17 X 17.</span>
4 0
3 years ago
Olivia ordered 24 cupcakes and a layer of cake. The layer cost $16 and the total cost of the order was $52. What was the price o
ArbitrLikvidat [17]
$16 was only for the layer.
$52-$16= cost of the cupcakes in total.
$36=cost of all cupcakes
36/24= cost of one cupcake
1.5= cost of one cupcake

each cupcake costs $1.50
4 0
3 years ago
Read 2 more answers
What values of c and d make the equation true?
saul85 [17]

Answer:

Third option.

Step-by-step explanation:

You need to cube both sides of the equation. Remember the Power of a power property:

(a^m)^n=a^{mn

\sqrt[3]{162x^cy^5}=3x^2y(\sqrt[3]{6y^d})\\\\(\sqrt[3]{162x^cy^5})^3=(3x^2y(\sqrt[3]{6y^d}))^3\\\\162x^cy^5=27x^6y^36y^d

According to the Product of powers property:

(a^m)(a^n)=a^{(m+n)

Then. simplifying you get:

162x^cy^5=162x^6y^{(3+d)}

Now you need to compare the exponents. You can observe that the exponent of "x" on the right side is 6,  then the exponent of "x" on the left side must be 6. Therefore:

c=6

You can notice that the exponent of "y" on the left side is 5,  then the exponent of "x" on the left side must be 5 too. Therefore "d" is:

3+d=5\\d=5-3\\d=2

4 0
3 years ago
Help me with this yes im lazy 2 pages thats it.
valentinak56 [21]

Answer:

2.)\frac{1}{4}/3=\frac{1}{4}*\frac{1}{3}=\frac{1}{12} s yes she is correct

3.)\frac{1}{5}*\frac{1}{7}

4.)C\frac{1}{5}/2= \frac{2}{5},D\frac{1}{12}/5=\frac{1}{60},E

6.)\frac{1}{8}/3=\frac{1}{24}

Step-by-step explanation:

im not very good at word problems so i didnt do the secnd page sorry

5 0
3 years ago
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