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REY [17]
2 years ago
14

Ausbin decides to use khan academy

Mathematics
2 answers:
77julia77 [94]2 years ago
5 0
So? what’s the problem?
gulaghasi [49]2 years ago
4 0

Answer:

So?

Step-by-step explanation:

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What is it !, help !
Gala2k [10]

Answer:

an isosceles triangle

Step-by-step explanation:

it has two equal sides so this is isosceles triangle

7 0
3 years ago
The diagonal length of a rectangle is 25 inches, and the length of the rectangle is 9 inches.
diamong [38]

Answer:

Option C is the right answer.

Step-by-step explanation:

Given that:

Length of diagonal = 25 inches

Length of rectangle = 9 inches

Width of rectangle will be one of the two legs of right angled triangle and the diagonal will be the hypotenuse.

Using Pythagorean theorem;

a^2+b^2=c^2\\(9)^2+w^2=(25)^2\\81 + w^2 = 625 \\w^2 = 625-81\\w^2 = 544

Taking square root;

\sqrt{w^2}=\sqrt{544}\\w=23.3

Therefore,

Option C is the right answer.

3 0
3 years ago
Can somebody please help me solve this problmem ?
frez [133]

Answer:

I believe that its 0.22

Step-by-step explanation:

5 0
3 years ago
State the gradients and the y intercepts of y=2x+6​
LekaFEV [45]

Answer:

y-intercept: Put x = 0 in the equation y = 2x - 6 and solve for x. The y-intercept is -6.

6 0
3 years ago
PLEASE HELP! WILL GIVE 70 POINTS!!
Tresset [83]

Answer:

A=189\ mm^2

Step-by-step explanation:

<u>Surface Areas </u>

Is the sum of all the lateral areas of a given solid. We need to compute the total surface area of the given prism. It has 5 sides, two of them are equal (top and bottom areas) and the rest are rectangles.

Computing the top and bottom areas. They form a right triangle whose legs are 4.5 mm and 6 mm. The area of both triangles is

\displaystyle A_t=2*\frac{b.h}{2}=b.h=(4.5)(6)=27 mm^2

The front area is a rectangle of dimensions 7.7 mm and 9 mm, thus

A_f=b.h=(7.5)(9)=67.5 \ mm^2

The back left area is another rectangle of 4.5 mm by 9 mm

A_l=b.h=(4.5)(9)=40.5  \ mm^2

Finally, the back right area is a rectangle of 6 mm by 9 mm

A_r=b.h=(6)(9)=54 \ mm^2

Thus, the total surface area of the prism is

A=A_t+A_f+A_l+A_r=27+67.5+40.5+54=189\ mm^2

\boxed{A=189\ mm^2}

4 0
3 years ago
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