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2 years ago

What is the answers to part a and part b

Mathematics

1 answer:

yarga [219]2 years ago

4 0

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<img src="https://tex.z-dn.net/?f=2%20%20%5Csqrt%7B2%7D%20" id="TexFormula1" title="2 \sqrt{2} " alt="2 \sqrt{2} " align="absm

True [87]

Answer:

Step-by-step explanation:

The square root of 2 is 1 and 1 multpied by 2 = 1

$2\sqrt{2} \\2(1)=2$

7 0

2 years ago

Find the 11th term of the arithmetic sequence. a3 = 20.5 and a8 = 13, a11 = ______. ...?

lianna [129]

In order to solve for a nth term in an arithmetic sequence, we use the formula written as:

an = a1 + (n-1)d

where an is the nth term, a1 is the first value in the sequence, n is the term position and d is the common difference.

First, we need to calculate for d from the given values above.
a3 = 20.5 and a8 = 13


an = a1 + (n-1)d
20.5 = a1 + (3-1)d

an = a1 + (n-1)d
13 = a1 + (8-1)d

a1 = 23.5
d = -1.5

The 11th term is calculated as follows:

a11 = a1 + (n-1)d
a11= 23.5 + (11-1)(-1.5)
a11 = 8.5

8 0

2 years ago

What is the value of the expression i 0 × i 1 × i 2 × i 3 × i 4?

astraxan [27]

ANSWER

The value of the expression is
$- 1$

EXPLANATION

Method 1: Rewrite as product of
${i}^{2}$

The expression given to us is,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4}$

We use the fact that
${i}^{2} = - 1$
to simplify the above expression.

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0} \times {i}^{1} \times {i}^{3} \times {i}^{2} \times {i}^{4}$

This implies,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0} \times {i}^{2} \times {i}^{2} \times {i}^{2} \times {i}^{2} \times {i}^{2}$

We substitute to obtain,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = 1\times - 1 \times - 1 \times - 1\times - 1 \times - 1$

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = 1\times 1 \times 1 \times - 1 = - 1$

Method 2: Use indices to solve.

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0 + 1 + 2 + 3 + 4}$

This implies that,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{10}$

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = ( {{i}^{2}} )^{5}$

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = ( - 1 )^{5} = - 1$

8 0

3 years ago

Read 2 more answers

Plz help I will give brainliest

arsen [322]

Answer:

#8. M = -8/9

#9. M = 3/5

6 0

2 years ago

Ms. Liebowitz has a choice of driving or flying from Morgantown, West Virginia to Washington, D.C. for a one-day business trip.

den301095 [7]

Answer:

Step-by-step explanation:

If she travels by air, she will be able to work seven hours in D.C. work four hours once there. Her expected income from each hour of work in D.C. is $40. This means that the total amount that she earns in 7 hours would be

40 × 7 = $280

if she drives, she will only have time to work four hours once there. This means that the total amount that she earns in 4 hours would be

40 × 4 = $160

The difference in both amounts would be

280 - 160 = $120

she will chose to fly if and only if the price differential (air cost minus driving cost) is less than $120

7 0

3 years ago