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son4ous [18]
3 years ago
15

Keiko, Dale, and Jose have a total of $107 in their wallets. Jose has 3 times what Dale has. Keiko has $8 less than Dale. How mu

ch does each have?
Amount in Keiko's wallet: $
Amount in Dale's wallet: $
Amount in Jose's wallet: $
Mathematics
1 answer:
olga2289 [7]3 years ago
6 0

Answer:

Amount in Dale's wallet :$23

Amount in Keiko's wallet :$15

Amount in Jose's wallet:  $69

Step-by-step explanation:

Let the money in Dale's wallet be $X

Given Jose has 3 times money than what Dale has.

if Dale has $X then Jose has $3X.

Also Keiko has $8 less than Dale

if Dale has $X then Keiko has $X - $8

Also Keiko, Dale, and Jose have a total of $107 in their wallets.

Writing this in form of mathematical expression with their value of money in terms of X we have given below equation.

$X + $3X + $X - $8 = $107

=> $5X - $8 = $107

=> $5X  = $107 + $8 = $115

=> X = $115/5 = $23.

Amount in Dale's wallet = $X   = $23

Amount in Keiko's wallet = $X - $8 = $23 - $8 =$15

Amount in Jose's wallet = $3X = $3*23 = $69

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Step-by-step explanation:

REMEMBER:
An isosceles triangle ABC with base BC = ‘b' & height AD = ‘h' & its equal sides =13 cm & area = 60 cm²

Using the formulas

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There are 2 solutions for b

b=2\sqrt{2}   \frac{A}{\sqrt{a^2+\sqrt{a^4-4A^2} } } =2*\sqrt{2} *\frac{60}{\sqrt{13^2+\sqrt{13^4-4*60^2} } } ≈ 10cmb=2\sqrt{2}   \frac{A}{\sqrt{a^2+\sqrt{a^4-4A^2} } } =2*\sqrt{2} *\frac{60}{\sqrt{13^2-\sqrt{13^4-4*60^2} } }=24cm

Less complex:

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