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Mekhanik [1.2K]
3 years ago
10

!!!PLEASE HELP ME !!! AND INCLUDE AN EXPLANATION

Mathematics
1 answer:
Ede4ka [16]3 years ago
3 0

Since you have the 42-deg angle and the length of the opposite side, 31, you can use the Law of Sines.


\dfrac{a}{\sin A} = \dfrac{b}{\sin B} = \dfrac{c}{\sin C}


We will use the law of sines first to find x.

Once we know x, we can find the angle opposite y.

Then we can find y.


\dfrac{31}{\sin 42^\circ} = \dfrac{37}{\sin x}


\sin x = \dfrac{37\sin 42^\circ}{31}


\sin x = 0.798639


x = \sin^{-1} 0.798639 = 53^\circ


Let z = the angle opposite y.


z + 42 + 53 = 180


z = 85

\dfrac{31}{\sin 42^\circ} = \dfrac{y}{\sin 85^\circ}


y = \dfrac{31 \sin 85^\circ}{\sin 42^\circ}


y = 46.2


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anastassius [24]
4) x=16
Vertical angles have equal angles when two lines intersect, which they do in this case. 
3x-3=2x+13
Solve for x:
x=16

5) 34 degrees
Lines AK and MJ bisect each other perpendicually, so <ADJ is 90 degrees. 
4x+3x-8=90
7x-8=90
7x=98
x=14
<CDJ=3x-8
=3(14)-8
=34 degrees

Hope this helps :)

6 0
3 years ago
What is the next term of the geometric sequence? 72,36,18
MissTica

Answer:

9

Step-by-step explanation:

The ratio is 1/2 so the next term would always be half of the previous one.

- 72 times 1/2 is 36

-36 times 1/2 is 18

-18 times 1/2 is 9. So the answer is 9

5 0
3 years ago
In an arithmetic sequence, t4 + t5 + t6 = 300, and t15 +t16+ t17 = 201. Find t18.
stiks02 [169]
In an arithmetic sequence:
Tn=t₁+(n-1)d

t₄=t₁+(4-1)d=t₁+3d
t₅=t₁+(5-1)d=t₁+4d
t₆=t₁+(6-1)d=t₁+5d

t₄+t₅+t₆=(t₁+3d) +(t₁+4d)+(t₁+5d)=3t₁+12d

Therefore:
3t₁+12d=300    (1)


t₁₅=t₁+(15-1)d=t₁+14d
t₁₆=t₁+(16-1)d=t₁+15d
t₁₇=t₁+(17-1)d=t₁+16d

t₁₅+t₁₆+t₁₇=(t₁+14d)+(t₁+15d)+(t₁+16d)=3t₁+45d

Therefore:
3t₁+45d=201    (2)

With the equations (1) and (2) we make an system of equations:

3t₁+12d=300
3t₁+45d=201

we can solve this system of equations by reduction method.

  3t₁+12d=300
-(3t₁+45d=201)
-----------------------------
       -33d=99      ⇒d=99/-33=-3

3t₁+12d=300
3t₁+12(-3)=300
3t₁-36=300
3t₁=300+36
3t₁=336
t₁=336/3
t₁=112

Threfore:

Tn=112+(n-1)(-3)
Tn=112-3n+3
Tn=115-3n

Now, we calculate T₁₈:

T₁₈=115-3(18)=115-54=61

Answer: T₁₈=61




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