1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nignag [31]
3 years ago
9

The function with a rate of change of 3/2 whose graph passes through the point (4,10.5)

Mathematics
1 answer:
tamaranim1 [39]3 years ago
4 0

Answer:

y = 1.5x+4.5

Step-by-step explanation:

Let's try to fit this into slope-intercept form, which is y=mx+b, where m=slope and b=y-intercept.

Rate of change means slope, so m=3/2 = 1.5.

y = 3/2x+b

We can plug in the given point, remembering that it's in the form (x,y), so x=4, y=10.5.

y = 3/2x+b

10.5 = 3/2*4 + b

4.5 = b

Plug b back in.

y = 1.5x+4.5

You might be interested in
Battery packs in electric go-carts need to last a fairly long time. The run-times (time until it needs to be recharged) of the b
pav-90 [236]

Answer:

The minimum level for which the battery pack will be classified as highly sought-after class is 2.42 hours

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 2, \sigma = 0.33

What is the minimum level for which the battery pack will be classified as highly sought-after class

At least the 100-10 = 90th percentile, which is the value of X when Z has a pvalue of 0.9. So it is X when Z = 1.28.

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{X - 2}{0.33}

X - 2 = 0.33*1.28

X = 2.42

The minimum level for which the battery pack will be classified as highly sought-after class is 2.42 hours

4 0
3 years ago
Sal recorded the number of crackers in each snack-sized package he opened.
Natasha2012 [34]
It’s going to be 99 but I’m not sure
3 0
3 years ago
Read 2 more answers
Marla is looking for a new car. She has test-driven two cars but can only purchase one. The probability that she will purchase c
marissa [1.9K]
The probability that she won't buy either car is .10. You add the two probabilities that were previously stated and then subtract them from 1.00. 

.52 + .38 = .90

1.00 - .90 = .10
6 0
3 years ago
Read 2 more answers
3x^2-5=43 how do i solve this using the square root property
slava [35]

Answer:

x = 4

x = -4

Step-by-step explanation:

bro i dont know but i hope this help a little, sorry

4 0
4 years ago
Please help simplify: 5bc^4-13bc^4
kvv77 [185]
I hope this helps you




-8bc^4
4 0
3 years ago
Other questions:
  • Same this for me but 6,912 and 288 please help
    9·1 answer
  • Multiple Choice The opposite of –4 is A. 4. B. –4. C. –(–(–4)). D. –|4|.
    5·2 answers
  • It costs more to produce defective items - since they must be scrapped or reworked - than it does to produce non-defective items
    9·1 answer
  • Please help asap i will mark branlist promise
    7·1 answer
  • Windows are cleaned at a house every 7 days.
    9·1 answer
  • PLEASE HELP!! I WILL GIVE BRAINLIEST!!!
    6·2 answers
  • If one pear costs 3$ how much of a pear can you get for 1$?
    11·2 answers
  • A survey shows that three out of every five teenagers at a particular school with cell phones use text messaging. In a group of
    11·1 answer
  • Calculate the cost for using 9,5 in one month and then add vat 15%to the bill​
    11·1 answer
  • Given the graph of the quadratic function, identify the solutions.
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!