Remark
The general formula for these types of questions is
(x1 + k(x2 - x1) ) , (y1 + k(y2 - y1))
<u>Problem 1 -- Point G</u>
Givens
(x1,y1) is the starting point which in this case is (-3, -3)
(x2,y2) is the ending point which in this case is (6 , -3)
k = 1/4
Sub and solve
(-3 + 1/4(6 - - 3), - 3+ 1/4(- 3 - - 3)
(-3 + 1/4(9) , - 3 + 1/4 (-3 + 3)
(-3 + 9/4, -3 + 1/4(0) )
(-12/4 + 9/4 , -3)
(-3/4 , - 3) Answer
<u>Problem 2 Point F Much harder</u>
Givens
(x1,y1) = (-3 , -1)
(x2,y2) = (6, - 3)
k = 3/4
Sub and solve
(-3 + 3/4(6 - - 3) , -1 + 3/4(-3 - - 1) )
(-3 + 3/4(9) , - 1 + 3/4(-2) )
(-3 + 27/4 , -1 - 6/4 )
(-12/4 + 27/4, -4/4 - 6/4)
( 15/4 , - 10/4) <<<<<< Answer Part B
