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Readme [11.4K]
3 years ago
7

Anyone who is good at math please help !

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
8 0

For the problem the Answer is ST

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What is the value of a in the equation 5a – 10b = 45, when b = 3?
andriy [413]
To get the answer we have to substitute b=3 and solve it.
5a-10b=45
5a-10*3=45
5a-30=45         /+30  add 30 both sides
5a-30+30=45+30
5a=75              /:5    divide both sides by 5
5a:5=75:5
a=15 - its the answer
8 0
3 years ago
Read 2 more answers
Find the total surface area.
Damm [24]
I think it’s 3 (900 cm2) sorry if it’s wrong.
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1 year ago
To find the height of a tower, a surveyor positions a transit the is 2 meters tall at a spot of 40 meters from the base of the t
Mrac [35]
The height of the tower roughly equals 41.421 meters.
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4 years ago
Draw the graph of the line that is perpendicular to Y= 4X +1 and goes through the point (2, 3)
spayn [35]

Given:

\begin{gathered} y=4x+1 \\ \text{ point }(2,3) \end{gathered}

To find:

Draw a graph of a line that is perpendicular to the given line and passing through a given point.

Explanation:

As we know that relation between two slopes of perpendicular slopes of lines:

m_1.m_2=-1

Slope of given line y = 4x + 1 is:

m_2=4

So, the slope of line perpendicular to given line is:

m_2=-\frac{1}{4}

Also, so line equation that is perpendicular to given line is:

y=-\frac{1}{4}x+c...........(i)

Also, the required line is passing thorugh given point (2, 3), i.e.,

\begin{gathered} 3=-\frac{1}{4}(2)+c \\ c=3+\frac{1}{2} \\ c=\frac{7}{2} \end{gathered}

So, line equation that is perpendicular to given line is:

y=-\frac{1}{4}x+\frac{7}{2}

The required graph of line is:

8 0
2 years ago
20 POINTS, please help!!Factor the algebraic expression below in terms of a single trigonometric function.
Lubov Fominskaja [6]
Csc²x - 1

1/sin²x  -  1

1/sin²x  -  sin²x / sin²x

(1 - sin²x) / sin²x

Recall that sin²x + cos²x = 1

So cos²x = 1 - sin²x

So we can replace numerator to cos²x

cos²x / sin²x
 
= cot²x

Final answer: cot²x
6 0
3 years ago
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