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Simora [160]
3 years ago
9

1 gallon of batter is poured equally into 4 bowls. How many gallons of batter are in each bowl?

Mathematics
1 answer:
yarga [219]3 years ago
5 0

Answer:

1/4 of a gallon otherwise known as 1 quart.

Step-by-step explanation:

This is because you are spliting one thing into four parts so each bowl would have 1/4 of the gallon.

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A right triangle has a hypotenuse length of 13 units. One leg has a length of 12 units. Which equation can be used to determine
irinina [24]

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The length of the other leg is 12

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Pleasee! Which expression is equivalent to the given expression? Assume the denominator does not equal zero.
Ilia_Sergeevich [38]

Answer:

A. 2y^4 over x^2

Step-by-step explanation:

4x^4y^6 ÷ 7x^8y^2

First, you will find the GCF of the equation which is: 7x^4y^2 .

Then, you will divide both of the equation by the GCF which will become:

14x^4y^6 ÷ 7x^4y^2 = 2y^4

7x^8y^2 ÷ 7x^4y^2 = x^2

Hence, the final answer is 2y^4 over x^2

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Answer:

it would be more of the second answer

Step-by-step explanation:

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3 years ago
Use this information to answer the questions. University personnel are concerned about the sleeping habits of students and the n
Oksanka [162]

Answer:

z=\frac{0.554 -0.5}{\sqrt{\frac{0.5(1-0.5)}{377}}}=2.097  

p_v =P(Z>2.097)=0.018  

If we compare the p value obtained and the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of  students reported experiencing excessive daytime sleepiness (EDS) is significantly higher than 0.5 or the half.

Step-by-step explanation:

1) Data given and notation

n=377 represent the random sample taken

X=209 represent the students reported experiencing excessive daytime sleepiness (EDS)

\hat p=\frac{209}{377}=0.554 estimated proportion of students reported experiencing excessive daytime sleepiness (EDS)

p_o=0.5 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is higher than 0.5:  

Null hypothesis:p\leq 0.5  

Alternative hypothesis:p > 0.5  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.554 -0.5}{\sqrt{\frac{0.5(1-0.5)}{377}}}=2.097  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(Z>2.097)=0.018  

If we compare the p value obtained and the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of  students reported experiencing excessive daytime sleepiness (EDS) is significantly higher than 0.5 or the half.

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Pamela Is 10 years older than Jiri. The sum of their ages is 96. What is Jiri’s age
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43 is jiri and 53 is pamela
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