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stealth61 [152]
3 years ago
15

5x+13=13 is this a one soulution or not

Mathematics
1 answer:
qaws [65]3 years ago
5 0

[ Answer ]

\boxed{One \ Solution}

[ Explanation ]

5x + 13 = 13

Solve Equation To Figure Out Solution(s)

Subtract 13 From Both Sides:

5x + 13 - 13 = 13 - 13

Simplify:

5x = 0

Divide Both Sides By 5:

\frac{5x}{5} = \frac{0}{5}

Simplify:

X = 0

X = 0. This Means, There Is One Solution To This Algebraic Equation

\boxed{[ \ Eclipsed \ ]}

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Rksheet
VLD [36.1K]

See below for the terms, coefficients, and constants in the variable expressions

<h3>How to determine the terms, coefficients, and constants in the variable expressions?</h3>

To determine the terms, coefficients, and constants, we use the following instance:

ax + by + c

Where the variables are x and y

  • Then the terms are ax, by and c
  • The coefficients are a and b
  • The constant is c

Using the above as guide, we have:

A) 2b + 2ac+5

  • Terms: 2b, 2ac, 5
  • Coefficient: 2, 2 and 5
  • Constant 5

B) 34abx + 16y +1

  • Terms: 34abx, 16y, 1
  • Coefficient: 34ab, 16
  • Constant: 1

C) st +4u + v

  • Terms: st, 4u, v
  • Coefficient: 4

D) 14xy + 6

  • Terms: 14xy, 6
  • Coefficient: 14, 6
  • Constant 6

E) 14x + 12y

  • Terms: 14x, 12y
  • Coefficient: 14, 12

F) 3+ 6-7+a

  • Terms: 3, 6, -7, a
  • Coefficient: 1
  • Constant: 3, 6, -7

Read more about terms, coefficients, and constants at:

brainly.com/question/14625487

#SPJ1

5 0
1 year ago
suzie spent 3 1/2 hours at the beach. she spent 45 minutes playing in the sand and the rest of the time playing in the water. ho
Anika [276]

Answer:

2 hours and 45 min

Explanation:

3 hours+30 minutes

subtract 30

3 hours

subtract 15

2 hours and 45 min

6 0
2 years ago
What are the like terms in the expression 8+x²-4x³+5x+2x²​
Virty [35]
X^2 and 2x^2 are alike.
They both have variables and the same exponent
4 0
3 years ago
Explian how to tell wherher (2,-1) is a solution of the equation y=3x-2
jolli1 [7]

Answer:

it is not a solution

Step-by-step explanation:

You would plug them in

-1=3(2)-2

-1=6-2

-1=4

4 0
3 years ago
Read 2 more answers
An automobile achieves a gas mileage of 30.5 mi/gal. how many kilometers can it travel on 1.5 l of gasoline?
Ksivusya [100]
Gas mileage = 30.5 mi/gal
Volume of gas = 1.5 l 

Note that 1 liter = 0.264172 gallons
Therefore
1.5 l = (1.5 l)*(0.264172 gal/l) = 0.3963 gal

Distance traveled is (Gas mileage, mi/gal)*(Gal of gas)
= (30.5)(0.3963) = 12.087 mi

Answer: 12 mi  (nearest integer)

3 0
3 years ago
Read 2 more answers
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