?? can someone help plzzz

Mathematics

1 answer:

Stolb23 [73]3 years ago

3 0

Answer:52,425

Step-by-step explanation: If you add all of the positive assets you end up with 15,050 but if you add 71,975 you get exactly 87,025 but when you add the liabilities you get -19,550 when you add those two numbers you get 52,425

Hope this helps!

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Data was collected for 300 fish from the North Atlantic. The length of the fish (in mm) is summarized in the GFDT below.

agasfer [191]

Answer:

Class Boundary = 1 between the sixth and seventh classes.

Step-by-step explanation:

Lengths (mm) Frequency

1. 140 - 143 1

2. 144 - 147 16

3. 148 - 151 71

4. 152 - 155 108

5. 156 - 159 83

6. 160 - 163 18

7. 164 - 167 3

The class boundary between two classes is the numerical value between the starting value of the higher class, which is 164 for the 7th class in this case, and the ending value of the class of the lower class, which is 163 for the 6th class in this case.

Therefore the class boundary between the sixth and seventh classes

= 164 - 163 = 1

Therefore Class Boundary = 1.

It can be seen that class boundary for the frequency distribution is 1.

If we take the difference between the lower limits of one class and the lower limit of the next class then we will get the class width value.

Therefore, Class width,

w = lower limit of second class - lower limit of first class

= 144 - 140

= 4

7 0

3 years ago

You randomly draw a marble out of a bag that contains 20 total marbles. 12 of the marbles in the bag are blue.

Advocard [28]

Answer:

$P(Blue)=0.60$

Step-by-step explanation:

Probability: $Probability\ of\ an\ event=\frac{favourable\ outcome}{total\ outcome}$

$Total\ marbles=20\\\\Hence\ total\ outcomes=20\\\\Blue\ marbles=12\\\\Hence\ favourable\ outcomes=12\\\\P(Blue)=\frac{12}{20}\\\\P(Blue)=\frac{2\times 6}{2\times 10}\\\\P(Blue)=\frac{6}{10}\\\\P(Blue)=0.60$