Answer:
6 35/100 or six and 35 of 100
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
AB ll CD
what grade r u in btw ?
Answer:
0.87
Step-by-step explanation:
we know that
A half-acre is equal to----------> ![2,023.43\ m^{2}](https://tex.z-dn.net/?f=2%2C023.43%5C%20m%5E%7B2%7D)
Let
x---------> the length side of the building lot
y--------> the width side of the building lot
A------> Area of the building lot
x=5y-------> equation 1
![A=2,023.43\ m^{2}](https://tex.z-dn.net/?f=A%3D2%2C023.43%5C%20m%5E%7B2%7D)
![A=x*y](https://tex.z-dn.net/?f=A%3Dx%2Ay)
--------> equation 2
substitute equation 1 in equation 2
![2,023.43=[5y]*y](https://tex.z-dn.net/?f=2%2C023.43%3D%5B5y%5D%2Ay)
![5y^{2}= 2,023.43\\y^{2}= 404.686\\y= 20.11\ m](https://tex.z-dn.net/?f=5y%5E%7B2%7D%3D%202%2C023.43%5C%5Cy%5E%7B2%7D%3D%20404.686%5C%5Cy%3D%2020.11%5C%20m)
<u>Find the value of x</u>
![x=5y---> x=5*20.11--> x=100.55 m](https://tex.z-dn.net/?f=x%3D5y---%3E%20x%3D5%2A20.11--%3E%20x%3D100.55%20m)
therefore
<u>the answer is</u>
the dimensions of the building lot are 100.55 m* 20.11 m
Answer:
9
Step-by-step explanation:
The first simplification we can make is to replace 6^0 with 1.
The first rules of exponents we can apply are ...
<em>(a·b)^c = a^c·b^c</em> . . . . . . similar to the distributive property
<em> (a^b)^c = a^(b·c)</em>
This reduces your expression to ...
![(2^8\cdot 3^{-5})^{-2}\cdot\left(\dfrac{3^{-2}}{2^3}\right)^4\cdot 2^{28}=2^{8(-2)}\cdot 3^{-5(-2)}\cdot\dfrac{3^{-2(4)}}{2^{3(4)}}\cdot 2^{28}\\\\=2^{-16}\cdot 3^{10}\cdot\dfrac{3^{-8}}{2^{12}}\cdot 2^{28}](https://tex.z-dn.net/?f=%282%5E8%5Ccdot%203%5E%7B-5%7D%29%5E%7B-2%7D%5Ccdot%5Cleft%28%5Cdfrac%7B3%5E%7B-2%7D%7D%7B2%5E3%7D%5Cright%29%5E4%5Ccdot%202%5E%7B28%7D%3D2%5E%7B8%28-2%29%7D%5Ccdot%203%5E%7B-5%28-2%29%7D%5Ccdot%5Cdfrac%7B3%5E%7B-2%284%29%7D%7D%7B2%5E%7B3%284%29%7D%7D%5Ccdot%202%5E%7B28%7D%5C%5C%5C%5C%3D2%5E%7B-16%7D%5Ccdot%203%5E%7B10%7D%5Ccdot%5Cdfrac%7B3%5E%7B-8%7D%7D%7B2%5E%7B12%7D%7D%5Ccdot%202%5E%7B28%7D)
Now we can apply another two rules of exponents:
<em> (a^b)(a^c) = a^(b+c)</em>
<em> 1/a^b = a^-b</em>
Using these, we have ...
![=2^{-16-12+28}\cdot 3^{10-8}\\\\=2^0\cdot 3^2\\\\=1\cdot 9=9](https://tex.z-dn.net/?f=%3D2%5E%7B-16-12%2B28%7D%5Ccdot%203%5E%7B10-8%7D%5C%5C%5C%5C%3D2%5E0%5Ccdot%203%5E2%5C%5C%5C%5C%3D1%5Ccdot%209%3D9)
The value of the expression is 9.