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Elden [556K]
3 years ago
14

The amounts of Cathy’s last six clothing purchases were $109, $72, $99, $15, $99, and $89.

Mathematics
1 answer:
Brums [2.3K]3 years ago
7 0
A:yes;$15
b:no bc other than the $15 all the prices are all in the same range
c:it makes the overall shape drop
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A trinidadian who is planning to visit Canada changed $3192 to canadian currency. How many $ did the triodion received
DanielleElmas [232]

Answer:

$3934

Step-by-step explanation:

We know that the currency of different countries are different.

So, one US dollar = 1.23 Canadian dollar

Given : $3192

A trinidadian changed some US dollar to Canadian dollar who plans to visit Canada.

He exchanged $3192.

Therefore,

1 US dollar = 1.23 Canadian dollar

The value of $ 3192 will be equal to = 1.23 x 3192

                                                            = $ 3933.96

                                                            ≈ $ 3934

Therefore,  triodion received =  $ 3934.

8 0
3 years ago
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brilliants [131]
The answer is going to be y^4 -13y^2 +36
I hope this helps!
Please make me brainiest

3 0
3 years ago
An investment is modeled by the function P = 2,500 (e) Superscript 0.025 t. What does 2,500 represent?
Setler [38]

Answer:

a

Step-by-step explanation:

they are right

3 0
4 years ago
Read 2 more answers
Which ratio is equivalent to the rate<br> 8 meters<br> 1 second<br> ?
KIM [24]
A unit rate where one is in the Denometer, so you would want to divide the bottom by 10.
5 0
2 years ago
How many positive integers $n$ satisfy $127 \equiv 7 \pmod{n}$? $n=1$ is allowed.
Svetllana [295]
Naturally, any integer n larger than 127 will return 127\equiv127\mod n, and of course 127\equiv0\mod127, so we restrict the possible solutions to 1\le n.

Now,

127\equiv7\mod n

is the same as saying there exists some integer k such that

127=nk+7

We have

\implies 120=nk

which means that any n that satisfies the modular equivalence must be a divisor of 120, of which there are 16: \{1,2,3,4,5,6,8,10,12,15,20,24,30,40,60,120\}.

In the cases where the modulus is smaller than the remainder 7, we can see that the equivalence still holds. For instance,

127=21\cdot6+1\iff127\equiv1\equiv7\mod6

(If we're allowing n=1, then I see no reason we shouldn't also allow 2, 3, 4, 5, 6.)
5 0
4 years ago
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