I have to determine the coordinates of the x-intercepts of the parabola. please help I need assistance with this practice proble
m.
1 answer:
The x-intercept of a graph refers to the points where the graph cuts or intersects the x-axis.
These are the x-values when y is equal to zero.
From the graph provided, the values of x when the graph cuts the x-axis are:
Therefore, the coordinates of the x-intercepts are:
The answer type is "Two points".
You might be interested in
Answer:
- y = -2(x -3)² +24
- 16 feet
Step-by-step explanation:
We expect the equation for y to be quadratic. Since the table is obviously symmetrical about x=3, we can start with the vertex form ...
y = a(x -3)² +b
Filling in the values from the first two table points, we get
For (x, y) = (0, 6):
6 = a(0 -3)² + b ⇒ 9a +b = 6
For (x, y) = (2, 22):
22 = a(2-3)² +b ⇒ a +b = 22
Subtracting the second equation from the first gives ...
(9a +b) -(a +b) = (6) -(22)
8a = -16 . . . . . . collect terms
a = -2 . . . . . . . . divide by 8
The second equation above tells us ...
b = 22 -a = 22 -(-2) = 24
So, our equation for y is ...
y = -2(x -3)² +24
__
The value of y for x=5 is ...
y = -2(5 -3)² +24 = 16
The height of the ball after 5 seconds is 16 feet.
