The volume of a square pyramid is (1/3)(area of base)(height of pyramid).
Here the area of the base is (10 ft)^2 = 100 ft^2.
13 ft is the height of one of the triangular sides, but not the height of the pyramid. To find the latter, draw another triangle whose upper vertex is connected to the middle of one of the four equal sides of the base by a diagonal of length 13 ft. That "middle" is 5 units straight down from the upper vertex. Thus, you have a triangle with known hypotenuse (13 ft) and known opposite side 5 feet (half of 10 ft). What is the height of the pyramid?
To find this, use the Pyth. Thm.: (5 ft)^2 + y^2 = (13 ft)^2. y = 12 ft.
Then the vol. of the pyramid is (1/3)(area of base)(height of pyramid) =
(1/3)(100 ft^2)(12 ft) = 400 ft^3 (answer)
Answer:
x=8.2
Step-by-step explanation:
First, figure out which trig function you are going to use.
In this problem you are dealing with the opposite side to the angle and the hypotenuse, and if you remember SOH CAH TOA, this requires sine.
sin (55) =opposite/hypotenuse
sin (55) =x/10
multiply both sides by 10 to get 10 * sin (55) = x
10 * sin (55) = 8.2
NUMBER 2 is 240 because 6 times 4 times 10 is equal to 240. I am still working on the others
Answer:
42 is an area
Step-by-step explanation:
Answer:
Step-by-step explanation:
The answer is D. Both are negative because they're both elevations below 0. However, -7 is higher, or closer to the regular level, because -10 is simply farther down.
