Answer:
let x=distance 105 mph train traveled
(456-x)=distance 85 mph train traveled
Travel time = distance/speed (equal in both directions)
x/105=(456-x)/85
85x=105*456-105x
190x=105*456
x=105*456/190=252 miles
travel time=252/105=2.4 hrs
ans:
The two trains will meet in 2.4 hrs
Step-by-step explanation:
there brainliest pls
Answer:
B. Train B
Step-by-step explanation:
We are told that Milford and Pinkerton is 300 miles away.
Train A leaves Milford at 10:00 am. There are 3 hours between 10:00 am to 1:00 pm. So let us find distance traveled by train A in 3 hours.



Since train A will cover 270 miles in 3 hours and distance between Milford and Pinkerton is 300 miles, therefore, train A will not arrive Pinkerton before 1:00 pm.
Since there are 5 hours between 8:00 am to 1:00 pm, so let us find distance traveled by train B in 5 hours.


Since train B will cover 350 miles in 5 hours, therefore, train B will arrive Pinkerton before 1:00 pm and option B is the correct choice.
A = L * W
A = 99
L = 2W + 7
99 = W(2W + 7)
99 = 2W^2 + 7W
-2W^2 - 7W + 99 = 0
(-2W + 11)(W + 9) = 0
-2W + 11 = 0
-2W = -11
W = -11/-2
W = 5.5
W + 9 = 0
W = -9 .....not this one because it is negative
so the width (W) = 5.5ft <====
L = 2W + 7 .....2(5.5) + 7 = 18 ft is the length (L) <==