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Orlov [11]
3 years ago
15

The curve through the ordered pairs (0,10), (1,5), (2,2.5) can be represented by the function f(x)= 10(0.5)^x. What is the multi

plicative rate of change of the function?
Mathematics
1 answer:
ArbitrLikvidat [17]3 years ago
3 0

Answer:

0.5

Step-by-step explanation:

The function is represented as y = f(x) = 10(0.5)^{x}

Now, it is clear from the function given above that, for x = 0,  y = f(x) = 10, and for x=1, f(x) = 5, and for x=2, f(x) = 2.5.

Therefore, the value of f(x) is multiplied each time by 0.5 for each unit increase in the value of x.

So, the multiplicative rate of change of the function is 0.5. (Answer)

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How does f(4) if f(x) = 2x work? how do i work this out?
sveta [45]
So just plug in the 4 wherever you see an x. so it is f(4)=2(4)
6 0
3 years ago
Suppose that the IQs of university​ A's students can be described by a normal model with mean 150150 and standard deviation 77 p
NeX [460]

Answer:

The probability that the​ student's IQ is at least 140 points is of 55.17%.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

University A: \mu = 150, \sigma = 77

a) Select a student at random from university A. Find the probability that the​ student's IQ is at least 140 points.

This is 1 subtracted by the pvalue of Z when X = 140. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{140 - 150}{77}

Z = -0.13

Z = -0.13 has a pvalue of 0.4483.

1 - 0.4483 = 0.5517

The probability that the​ student's IQ is at least 140 points is of 55.17%.

3 0
3 years ago
Solve for m:<br><br> -8m + 4 = 52
Virty [35]

Answer:

m = -6

Step-by-step explanation:

-8m + 4 = 52

-8m = 48

-8m/-8 = 48/-8

m = -6

8 0
2 years ago
Please help I gotta pass this test
Paraphin [41]

Answer:

h=128

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Find an equation for the nth term of the arithmetic sequence.
Irina18 [472]

Answer:

The equation of the nth term is an = -621 + 42n

Step-by-step explanation:

* Lets revise the arithmetic sequence

- There is a constant difference between each two consecutive numbers

- Ex:

# 2  ,  5  ,  8  ,  11  ,  ……………………….

# 5  ,  10  ,  15  ,  20  ,  …………………………

# 12  ,  10  ,  8  ,  6  ,  ……………………………

* General term (nth term) of an Arithmetic sequence:

- U1 = a  ,  U2  = a + d  ,  U3  = a + 2d  ,  U4 = a + 3d  ,  U5 = a + 4d

- Un = a + (n – 1)d, where a is the first term , d is the difference

  between each two consecutive terms

, n is the position of the term

* Lets solve the problem

∵ an = a + (n - 1)d

∴ a14 = a + (14 - 1)d

∴ a14 = a + 13d

∵ a14 = -33

∴ a + 13d = -33 ⇒ (1)

- Similar we can find another equation from a15

∵ a15 = a + (15 - 1)d

∴ a15 = a + 14d

∵ a15 = 9

∴ a + 14d = 9 ⇒ (2)

- We will solve equations (1) and (2) to find a and d

* Lets subtract equation (2) from equation (1)

∴ (a - a) + (13 - 14)d = (-33 - 9)

∴ -d = -42 ⇒ × both sides by -1

∴ d = 42

- Substitute this value of d in equation (1) or (2)

∵ a + 13d = -33

∵ d = 42

∴ a + 13(42) = -33

∴ a + 546 = -33 ⇒ subtract 546 from both sides

∴ a = -579

* Now lets write the equation of the nth term

∵ an = a + (n - 1)d

∵ a = -579 and d = 42

∴ an = -579 + (n - 1) 42 ⇒ open the bracket

∴ an = -579 + 42n - 42

∴ an = -621 + 42n

* The equation of the nth term is an = -621 + 42n

6 0
3 years ago
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